判断下列矩阵能否对角化?若能对角化,求出相似变换矩阵: [tex=10.143x3.643]QN0fTQbn6M33pU3gx/S2sjGvxgBO0tPH5V57610H8Q1wT77DwaQGURbp2KEjIoWQLS8BK7/no+22/Bcn3Meo/uXgOxo+1cVbcsx7w8e5ComzKKt+PeobjW93V9QhFuAD[/tex][br][/br]
举一反三
- 判断下列矩阵能否对角化?若能对角化,求出相似变换矩阵:[br][/br][tex=6.214x2.786]3BT1BgBZQ5uJXxD5dg+w2+ZVVOTlsTvoSOF5eJKKHg1zsojoKHBDoWCvXiUaUuww2t2IibfiPOUZ652jnQIr8Q==[/tex]
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 说明S盒变换的原理,并计算当输入为110101时的S1盒输出。 [br][/br] n\m 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 S1 0 14 4 13 1 2 15 11 8 3 10 6 12 5 9 0 7 1 0 15 7 4 14 2 13 1 10 6 12 11 9 5 3 8 2 4 1 14 8 13 6 2 11 15 12 9 7 3 10 5 0 3 15 12 8 2 4 9 1 7 5 11 3 14 10 0 6 13
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}