• 2022-07-01
    若排列38i7j625为奇排列,则i=( ),j=( ).
    A: i=1,j=4
    B: i=4,j=1
    C: i=4,j=9
    D: i=9,j=4
  • A

    内容

    • 0

      for(i=4;i>1;i--)for(j=1;j

    • 1

      下列程序段能且只能显示1!、2!、3!、4!的值的是( )。 A: For i = 1 To 4 n = 1 For j = 1 To i n = n * j Next j MsgBox(n)Next i B: For i = 1 To 4 For j = 1 To i n = 1 n = n * j Next j MsgBox(n)Next i C: n = 1For i = 1 To 4 For j = 1 To 4 n = n * j MsgBox(n) Next jNext i D: n = 1j = 1Do While j <= 4 n = n * j j = j + 1LoopMsgBox(n)

    • 2

      以下程序的运行结果是【1】,其算法是【2】。 main() {int a[5]={9,6,8,3,-1},i,j,t,p; sort(a); for(i=0;i<=4;i++) printf("%3d",a[i]); } sort(int a[]) {int i,j,t,p; for(j=0;j<4;j++) {p=j; for(i=j;i<=4;i++) if(a[i] -1 3 6 8 9  选择法排序

    • 3

      以下程序段的输出结果是()。inti,j;for(i=1;i<4;i++){for(j=1;j<4;j++)printf("%d*%d=%d",i,j,i*j);printf("\n");}

    • 4

      下列程序段能分别正确显示1!、2!、3!、4!的值的是______。 A: For i = 1 To 4 n = 1 For j = 1 To i n = n * j MsgBox(n) Next jNext i B: For i = 1 To 4 For j = 1 To i n = 1 n = n * j Next j MsgBox(n)Next i C: n = 1For i = 1 To 4 For j = 1 To 4 n = n * j MsgBox(n) Next jNext i D: n = 1j = 1Do While j &lt;= 4 n = n * j MsgBox(n) j = j + 1Loop