• 2022-06-04
    给一段代码defis_odd(n):returnn%2==0newlist=filter(is_odd,[1,2,3,4,5,6,7,8,9,10])foriteminnewlist:print(item)其输出结果是?
    A: [2,4,6,8,10]
    B: [1,3,5,7,10]
    C: [1,3,5,7,9]
    D: [1,3,5,6,9]
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