A: X^y
B: Xy
C: X^^y
D: None of the mentioned
举一反三
- Which is the correct operator for power(Xy)? ( ) A: X^^y B: X^y C: None of the mentioned D: X**y
- 分解因式()x()3()y()-()2()x()2()y()2()+()xy()3()正确的是A.()xy()(()x()+()y())()2()B.()xy()(()x()2()﹣()2()xy()+()y()2())()C.()xy()(()x()2()+2()xy()﹣()y()2())()D.()xy()(()x()﹣()y())()2
- 设\(z = {e^u}\sin v,\;u = xy,\;v = x + y\)，则\( { { \partial z} \over {\partial y}}=\)( ) A: \(x{e^{xy}}\sin \left( {x + y} \right) + {e^{xy}}\cos \left( {x + y} \right)\) B: \(x{e^{xy}}\sin \left( {x + y} \right) \) C: \( {e^{xy}}\cos \left( {x + y} \right)\) D: \(x{e^{xy}}\sin \left( {x + y} \right) - {e^{xy}}\cos \left( {x + y} \right)\)
- 在下图中，已知斜截面上无应力，该x、y面上的应力分量满足关系 （ ）[img=363x330]1803be4a6959759.png[/img] A: σx>σy, τyx>τxy B: σx<σy, τxy=τxy C: σx>σy, τyx=τxy D: σx<σy, τyx>τxy
- 下列微分方程中，( )是齐次方程。 A: \( xy' = y(\ln y - \ln x) \) B: \( xy' + {y \over x} - x = 0 \) C: \( y' + {y \over x} = {1 \over { { x^2}}} \) D: \( y - y' = 1 + xy' \)
内容
- 0
设\(z = u{e^v}\)，\(u = {x^2} + {y^2}\)，\(v = xy\)，则\( { { \partial z} \over {\partial x}}=\) A: \({e^{xy}}({x^2}y + {y^3} + 2x)\) B: \({e^{xy}}({x}y^2 + {y^3} + 2x)\) C: \({e^{xy}}({x}y + {y^3} + 2x)\) D: \({e^{xy}}({x^2}y + {y^2} + 2x)\)
- 1
设f(x,y)=(xy)/(x^2+y) ,则 f(xy,x/y)=______ 。
- 2
设\(z = u{e^v}\)，\(u = x + y\)，\(v = xy\)，则\( { { \partial z} \over {\partial x}}=\) A: \({e^{xy}}(1 + xy + {y^2})\) B: \({e^{xy}}(1 + xy + {y^3})\) C: \({e^{xy}}(x+ xy + {y^2})\) D: \({e^{xy}}(y+ xy + {y^2})\)
- 3
设\(z = u{e^v}\)，\(u = {x^2} + {y^2}\)，\(v = xy\)，则\( { { \partial z} \over {\partial y}}=\)（ ）。 A: \({e^{xy}}({x}y^2 + {x^3} + 2y)\) B: \({e^{xy}}({x^2}y + {x^3} + 2y)\) C: \({e^{xy}}({x}y^2 + {x^3} + 2x)\) D: \({e^{xy}}({x}y+ {x^3} + 2y)\)
- 4
取个体域为整数集合，则下列公式中为真命题的是 。 A: ∃x∀y(x+y=2y) B: ∀x∀y(xy=y) C: ∀x∃y(xy=0) D: ∀x(xy=x)