举一反三
- 求函数\(y = {\left( {2x + 1} \right)^4}\)的导数为___________ 。
- 函数\(y = \ln \left( {1 + {x^2}} \right)\)的导数为( ). A: \( { { 2x} \over {1 + {x^2}}}\) B: \( - { { 2x} \over {1 + {x^2}}}\) C: \( { { 2x} \over {1 - {x^2}}}\) D: \( - { { 2x} \over {1 - {x^2}}}\)
- 求函数\(y = {\left( {2x + 1} \right)^2}\)的导数为_____。______
- 函数\(y = {\left( { - 2x + 1} \right)^4}\)的导数为( ). A: \( - 8{\left( { - 2x + 1} \right)^3}\) B: \(8{\left( { - 2x + 1} \right)^3}\) C: \(4{\left( { - 2x + 1} \right)^3}\) D: \(- 4{\left( { - 2x + 1} \right)^3}\)
- 函数\( y = \left( {x - 4} \right)\root 3 \of { { {\left( {x + 1} \right)}^2}} \)的极大值为( )。 A: 0 B: 2 C: 3 D: 4
内容
- 0
函数\(y = 1{\rm{ + }}{1 \over x}\)的导数为( ). A: \({\rm{ - }}{1 \over { { x^2}}}\) B: \({1 \over { { x^2}}}\) C: \(\ln \left| x \right|\) D: \( - \ln \left| x \right|\)
- 1
求函数$y = \root 3 \of {x + \sqrt x } $的导数$y' = $( ) A: ${{1 + 2\sqrt x } \over {\root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$ B: $ {{1 + 2\sqrt x } \over {6\root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$ C: $ {{1 + 2\sqrt x } \over {6\sqrt x \cdot \root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$ D: $ {{1 + 2\sqrt x } \over {\sqrt x \cdot \root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$
- 2
下列方程中,不是全微分方程的为( )。 A: \(\left( {3{x^2} + 6x{y^2}} \right)dx + \left( {6{x^2}y + 4{y^2}} \right)dy = 0\) B: \({e^y}dx + \left( {x \cdot {e^y} - 2y} \right)dy = 0\) C: \(y\left( {x - 2y} \right)dx - {x^2}dy = 0\) D: \(\left( { { x^2} - y} \right)dx - xdy = 0\)
- 3
函数\( y = \left( {2x - 5} \right)\root 3 \of { { x^2}} \)的驻点为x= _______ ______
- 4
函数$z=\arcsin\dfrac{1}{~\sqrt{x+y}~}$的定义域为( ) A: $\left\{(x,y)\left|~x+y\geq<br/>0\right.\right\}$; B: $\left\{(x,y)\left|~x+y\geq<br/>1~\text{或}~x+y\leq<br/>-1 \right.\right\}$; C: $\left\{(x,y)\left|~x+y\geq<br/>1\right.\right\}$; D: $\left\{(x,y)\left|~x+y\geq<br/>\dfrac{4}{~\pi^2~}\right.\right\}$.