下列方程具有什么形式的特解?[tex=7.357x1.429]eE9dXkpN2effVrNkAbXJmJACYUvMIQjNtInv/PSJdkuDQecD/6IAXdyK1G4Zk9zB[/tex]
举一反三
- 写出下列方程具有待定系数的特解形式:[tex=10.643x1.5]uDURn6KTVSzuxHB9PQPJUlsBLm5s+mvpb/VuFS4eQq1Iv1NOpxhjQyALs7T5iukwblWNdSCycmhFxOXEaj5IBQ==[/tex]
- 用待定系数法,求[tex=7.357x1.429]rjzw0bBUODiY66l+Mq83xF8OXzjohPF0UXGCnUNHcWu2E0rWZV9rQOBBDTp0UtsH[/tex]的一般解或特解
- 求解方程: [tex=7.357x1.429]C1cW9lHEhpjBlL80QKmte5eQ+mtahC5BYO+uJhNxP7jolhp/GAbStY6cPwgMtTqJ[/tex]
- 以4,9,1为为插值节点,求\(\sqrt x \)的lagrange的插值多项式 A: \( {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) B: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) C: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x +1) + {1 \over {24}}(x - 4)(x - 9)\) D: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) - {1 \over {24}}(x - 4)(x - 9)\)
- 输出九九乘法表。 1 2 3 4 5 6 7 8 9 --------------------------------------------------------------------- 1*1=1 2*1=2 2*2=4 3*1=3 3*2=6 3*3=9 4*1=4 4*2=8 4*3=12 4*4=16 5*1=5 5*2=10 5*3=15 5*4=20 5*5=25 6*1=6 6*2=12 6*3=18 6*4=24 6*5=30 6*6=36 7*1=7 7*2=14 7*3=21 7*4=28 7*5=35 7*6=42 7*7=49 8*1=8 8*2=16 8*3=24 8*4=32 8*5=40 8*6=48 8*7=56 8*8=64 9*1=9 9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81