用比值审敛法判别下列级数的收敛性:[tex=4.429x3.286]3PXegz5bAQsuTODB0U8KrA3izlr5vJZQ4cIy7FL7GUSqoHzdj3UavdWabIGEL/aKPxXPbg01F6BmU2+BqsAHRw==[/tex]
解:记[tex=4.714x2.429]wP6ZuWjJeKaGxPfnhoOOSVixMqzfem0Aqi8RrSaQ66ULd8qv9gekEJWUQDST0rWQ[/tex], 则[tex=28.071x2.786]OqU0SQaVHd2x+OGLCy0gvYudstXsA8dnxqkmKhl/YeV6o1IKIfkWHwdWgj3M7I2lsSit1mb6iK12mPZtvt3doSyXPePjyCc+f1qudYPDB+o9+iOroe+X92npVVJvH4NUqUcCmKmgY/1ds1eRVbetrvicWc4/mYZnc19ZxCq6wF+MSfPiN6OGtMA0uz0GbvY88JzQ73XShmeC4UKvFewhqaTrzNVWw0W+Y/ZLIM5TZvz4OwtAdqaKD1JfuNKs4dHawGRKMnwUPmHfI8Vrm8EM0ZdF44lS66sSKN9SV4oXkVRznxvGD4M8CtTM2hyXbgqsSzacTBlwNDj27f7gty0i9A==[/tex]由比值审敛法知级数收敛.
举一反三
- 用比值审敛法判别下列级数的收敛性:[tex=6.071x3.286]3PXegz5bAQsuTODB0U8KrJ5fQhmJUpPU1AcRYR69zJ+Ii8c7BuENQp8kershU5nb[/tex]
- 用比值审敛法判别下列级数的收敛性: [tex=2.857x3.286]3PXegz5bAQsuTODB0U8KrFUaLNi3OFIBCfOnMjnvEhJnRh7l0VsbFznEEcc3Ah7s[/tex]
- 用比值审敛法判别下列级数的收敛性: [tex=2.929x3.286]3PXegz5bAQsuTODB0U8KrCkqCRbrq4gf3I+Zs5YTNc4pgKV4fgxAeXIdXMGN2dlZ[/tex]
- 用比值审敛法判别下列级数的收敛性: [tex=5.286x3.286]3PXegz5bAQsuTODB0U8KrJvuDQfoRGtPfHZe7aeDK5Yy9PZzooRn0Ebwi8yDezB0[/tex]
- 用比值审敛法判别下列级数的收敛性:[tex=2.857x3.286]3PXegz5bAQsuTODB0U8KrJ5fQhmJUpPU1AcRYR69zJ8EzttHLKaNaN/1twrTntqw[/tex]
内容
- 0
利用柯西审敛定理判别级数的收敛性：[tex=4.429x3.286]VCAPAvn3gOPyP36rvxBwzyrZ1Cf2LlfLZmglkGd5c3tbQ67UHKLhdtu4UpW+SwIP[/tex] .
- 1
【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 2
用比较审敛法判别下列级数的收敛性:[tex=4.571x3.286]3PXegz5bAQsuTODB0U8KrPGyAMSABXUtqnatfYFkeojycXoL15k5S9/2/IiJp6Lq[/tex]
- 3
set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 4
用达朗贝尔比值审敛法判别级数的收敛性：[tex=3.286x2.714]ySadpvq7BrEZCGdcnD6+aevd/JTbI7k0NnQ/CvMpl2KEYzfufvUjxbiW4g9s5t/O[/tex]