对于整数集合[tex=0.714x1.0]/7todLbYOYvW5Rsrp6O7Ww==[/tex]，令[tex=6.643x1.357]ax4zP+Wr5wz0ARfBbrp9waAMUB1s61TLlP7Yu4BOy+Cy/KOHn7yw9niIeBGYgPrz[/tex]，[tex=8.929x1.357]PFGLrGMvedwO4MNlJVsyplebVf0W7nHhAw0xTacBg4Y/WLZM5gVCuFPSpFqk5Ugn[/tex]，[tex=8.929x1.357]XgugKbD32hjqZZkMC3ypTtPNIsIYEnrNirwHfWG3I/zc8LHyI7LBv3d0srkqRFbR[/tex]，则[tex=4.857x1.357]mtGvqREi5833jL/sB2KiWIiNhPhhtKNpDqb969m12FRAO9j+kejwSOWzUTzF4ql1[/tex]是[tex=0.714x1.0]/7todLbYOYvW5Rsrp6O7Ww==[/tex]的划分，试证明之。
举一反三
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 以下程序段实现的输出是（）。for(i=0;i<;=9;i++)s[i]=i;for(i=9;i>;=0;i--)printf("%2d",s[i]);[/i][/i] A: 9 7 5 3 1 B: 1 3 5 7 9 C: 9 8 7 6 5 4 3 2 1 0 D: 0 1 2 3 4 5 6 7 8 9
- 设X，Y为两个随机变量，且P{X ³0，Y ³ 0} = 3/7 , P{X ³ 0} = P{ Y ³ 0} = 4/7 ,则P{max(X, Y) ³ 0} = ( )． A: 1/7 B: 3/7 C: 4/7 D: 5/7