• 2022-06-19
    下面代码的执行结果是:( )ls= [“2020”, “20.20”, “Python”]ls.append(2020)ls.append([2020, “2020”])print(ls)
    A: [‘2020’, ‘20.20’, ‘Python’, 2020]
    B: [‘2020’, ‘20.20’, ‘Python’, 2020, [2020, ‘2020’]]
    C: [‘2020’, ‘20.20’, ‘Python’, 2020, [‘2020’]]
    D: [‘2020’, ‘20.20’, ‘Python’, 2020, 2020, ‘2020’]r
  • 举一反三