• 2022-06-19
    以下代码的输出结果是( )。 ls = ["2020", "20.20", "Python"] ls.append([2020, "2020"]) [br][/br]print(ls)
    A: ['2020', '20.20', 'Python', [2020, '2020']]
    B: ['2020', '20.20', 'Python', 2020, ['2020']]
    C: ['2020', '20.20', 'Python', 2020,]
    D: ['2020', '20.20', 'Python', 2020, '2020']
  • 举一反三