• 2022-06-19
    以下代码的输出结果是( )ls = [“2020”,”1903”,”Python”]ls.append(2050)ls.append([2020,”2020”])print(ls)
    A: [‘2020’,’1903’,’Python’,2020,[2050,’2020’]]
    B: [‘2020’,’1903’,’Python’,2020]
    C: [‘2020’,’1903’,’Python’,2050,[2020,’2020’]]
    D: [‘2020’,’1903’,’Python’,2050,[‘2020’]]
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