设 [tex=6.5x1.357]7XkBBbhA7jf032wamwuewEZb0nwqQozKVqOT8OF1VYo=[/tex][tex=21.5x2.429]EPaISH7F+7OFqeEao9lVbabBMqJc9T5WLEEflDE4Pv4v7wSF4+tJYdl1roqKfBa7xYr38pesYjVrh5sCaf9mOPdW+if+P0XITQ+1jIG+8hxeAB+s76od9t7Of/cZwef8rNoUW0p8BhTNWDW07rxzQPu/hnx6389bZczRurDlVwt1MC4WGpGnVPTIfJNnR2dQ[/tex]其中 [tex=0.857x1.0]0LfrJpvS3xl2uy5MsLMRTA==[/tex] 表示有理数 [tex=0.571x0.786]ZKO2xs0EgSemzoH7MSmYTA==[/tex] 化成既约分数后的分母。证明 [tex=2.786x1.357]g1Wo3ALRzTk0js5m9GO2sA==[/tex] 在[tex=0.857x1.0]m2DKAQtGuc1DyN3zyNlILg==[/tex] 上的二重积分不存在, 而两个累次积分存在。
举一反三
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 【单选题】请用地点定桩法在4分钟内记忆数字。 4 0 1 3 6 3 5 1 9 8 8 9 7 2 9 3 0 9 5 3 1 7 7 5 2 3 3 0 5 0 1 4 1 3 8 3 5 7 9 7 (5.0分) A. 已背 B. 未背
- 【单选题】Which of the following matrices does not have the same determinant of matrix B: [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -1, 0, -9,-5] A. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 0; -1, 0, -9, -5] B. [1, 3, 0, 2; -2, -5, 7, 4; 1, 0, 9, 5; -1, 0, -9, -5] C. [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -3, -5, -2, -1] D. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 1; -1, 0, -9, -5]