设二次型[tex=8.643x1.5]CKlOGn/4oc+CIjd/NrEXYL4dkmrBlW2GCC51Nn4jxKANXOvDx2kgU1OQ41Fvjv7S4wy3sQ/s+4w1gaNWiYzEfA==[/tex]经正交变换化为标准形[tex=3.643x1.5]7V9lHlsR3o+lQ4ZvsgESPk415mbTzLbIcA4VmB6X2UA=[/tex]，求[tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex]的特征值及[tex=1.143x1.357]m3nRCpZgU5gVkSZji8k5kw==[/tex].
举一反三
- 求解下列矩阵对策,其中赢得矩阵 [tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex] 为$\left[\begin{array}{llll}2 & 7 & 2 & 1 \\ 2 & 2 & 3 & 4 \\ 3 & 5 & 4 & 4 \\ 2 & 3 & 1 & 6\end{array}\right]$
- 若实对称矩阵[tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex]与矩阵[tex=7.786x3.5]opqi7S5YyIUs5JQiNQr2vJ+2NLxb3mgUQ8cog+A0uO2//e5NPySzN4MJqurCOu3PQ4sjWYw/glS+VBTLQqFwyMVpffnUZyoaZcZ5F5P77ABiD39SaSACFqXYjbIOp8DA[/tex]合同，求二次型[tex=8.643x1.5]CKlOGn/4oc+CIjd/NrEXYL4dkmrBlW2GCC51Nn4jxKANXOvDx2kgU1OQ41Fvjv7S4wy3sQ/s+4w1gaNWiYzEfA==[/tex]的规范形.
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 设矩阵 [tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex]与[tex=0.786x1.0]sHo1pKm+gjxjcUAJjHrarQ==[/tex] 相似, 其中[tex=8.643x3.643]3BT1BgBZQ5uJXxD5dg+w26muwh1xN1sRXO8Q3eF5f+iTpB6kD/3/7F/Sewwa3hxWs7TCQWFyZq0QSUW2LGcSxj3jay92Ev0sXUjwbpJxe2w84vpk6B1wjRlgxeXY7DUa[/tex], 已知矩阵 [tex=0.786x1.0]sHo1pKm+gjxjcUAJjHrarQ==[/tex]有特征值 1,2,3, 则 [tex=1.357x0.786]C5gMMrS05DsgTY0BSnf1fg==[/tex] A: 4 B: -3 C: -4 D: 3
- [tex=17.429x1.286]VoKfr1IIzGJmh8L2l120JqjixkQ1tL3XlyBgbwU9pvS9UKZRTovLmaVq8Zv4SelU6NNNx16xNXr2asYvjnme4w==[/tex][img=310x163]179b0f602527037.png[/img] 未知类型：{'options': ['0.5 s(2) 1 s(3) $2 s$(4) $4 s$', '\xa01 s(3) $2 s$(4) $4 s$', '2 s(4) $4 s$', '4 s'], 'type': 102}