证明 :存在唯一的连续函数[tex=10.714x1.357]89l0PlqxsoKvamVa6wUlKqY2doP24ASA3HTB5cfOJT8=[/tex] 满足开普勒方程 [tex=10.357x1.357]QszMMrB+Oe3XQJi2A7yyR+pyTVpV2DKmw3ytmJagzrhqszM/6FqKpcAC/K0dxhrNlbkF8k3TyWlqykv3n3PATw==[/tex]
举一反三
- 证明:有连续函数[tex=10.714x1.357]89l0PlqxsoKvamVa6wUlKqY2doP24ASA3HTB5cfOJT8=[/tex] 满足开普勒(Kepler)方程[tex=11.071x1.357]cK1NCp9ABSr6Cp6Y1hAeLNbyHP79UolOkOu7/jARjwbYUuX3oIPwQ/EuDAkl9HgZoFkMhjmhASDqHLdq3v1exw==[/tex]
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 假设“☆”是一种新的运算,若3☆2=3×4,6☆3=6×7×8,x☆4=840(x>0),那么x等于: A: 2 B: 3 C: 4 D: 5 E: 6 F: 7 G: 8 H: 9