举一反三
- 设[tex=2.571x1.357]swgG+fbKeBDkV392c1yLvwn7AbP0IJ3jaRWA7VIW+oY=[/tex]是格，对于任意[tex=3.5x1.214]KP32jHpwVA/ChU/BPW2kfg==[/tex]有[tex=9.143x1.357]dk2T/fDp+oxBH37nMt1efAwszbRlFicMz73t1cgEaT/eS1MQunWFfd17k1VMOF42TwldAsyMgakFJ8deQUBwqA==[/tex]。
- 设[tex=2.571x1.357]swgG+fbKeBDkV392c1yLvwn7AbP0IJ3jaRWA7VIW+oY=[/tex]是格，对于任意[tex=2.714x1.214]Pz9OQ44WQx3wVKEpY1ZcLQ==[/tex]有[tex=4.857x1.357]i8jpVPumd5ZqFN/uelljUQ==[/tex]。
- 设f(x)具有性质：[tex=8.571x1.357]8gPeznjMnng12qtkk9Vgczii1Sh4d1qJxc9iHYT5+YI=[/tex]证明：必有f(0)=0，[tex=5.5x1.357]rt5qCY7TXHcsFUQrD44nPA==[/tex]（p为任意正整数）
- 设[tex=2.571x1.357]swgG+fbKeBDkV392c1yLvwn7AbP0IJ3jaRWA7VIW+oY=[/tex]是分配格，对于任意[tex=3.5x1.214]ZcY7qu5Nv8mx7HQtL5txfA==[/tex]，若[tex=4.5x1.143]ZBDGSPFtRnStkCKr2bFpNw==[/tex]，则[tex=1.786x1.0]8YJZrMwcUdKQdYqa0pq/5g==[/tex]。
- 【单选题】Which of the following matrices does not have the same determinant of matrix B: [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -1, 0, -9,-5] A. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 0; -1, 0, -9, -5] B. [1, 3, 0, 2; -2, -5, 7, 4; 1, 0, 9, 5; -1, 0, -9, -5] C. [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -3, -5, -2, -1] D. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 1; -1, 0, -9, -5]
内容
- 0
>>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 1
设[tex=2.571x1.357]swgG+fbKeBDkV392c1yLvwn7AbP0IJ3jaRWA7VIW+oY=[/tex]是格，对于[tex=3.5x1.214]55zBl/pHvpcszo3USEAvsSVSy9Pw0Uf4OyY6LzYkrPI=[/tex]，若[tex=4.929x1.0]kNhFZ20CE87LNXYL+hOhrcSW6MOcxUlns3PVhL4jDic=[/tex]且[tex=4.5x1.143]ZBDGSPFtRnStkCKr2bFpNw==[/tex]，则[tex=2.357x1.0]5jrkpRnSDtC8g9/JG/UuuA==[/tex]。
- 2
set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 3
设X ~ N(2, 9)则Y = (X – 2 )/9 ~ N(0, 1).
- 4
设二维随机变量(X,Y)的联合分布列为 XY -1 0 1 -1 1 1/6 1/9 2/9 1/3 0 1/6则P{XY=1}为( ) A: 0 B: 1/6 C: 1/3 D: 2/3