对于数学表达式，正确的C语言表达式是（）
A: 2sqrt(x)+(a+b)/3sin(x)
B: 2sqrt(x)+(a+b)/(3sin(x))
C: 2*sqrt(x)+(a+b)/3/sin(x)
D: 2*sqrt(x)+(a+b/3*sin(x))
A: 2sqrt(x)+(a+b)/3sin(x)
B: 2sqrt(x)+(a+b)/(3sin(x))
C: 2*sqrt(x)+(a+b)/3/sin(x)
D: 2*sqrt(x)+(a+b/3*sin(x))
举一反三
- 对于数学表达式2x＋(a＋b)÷3sinx，对应的C表达式是() A: 2x+(a+b)/3sin(x) B: 2x+(a+b)/(3sin(x)) C: 2*x+(a+b)/3/sin(x) D: 2*x+(a+b/3/sin(x))
- 1802fa0b3e3fac1.png,求y的一阶导数 A: 3sin^2(x/3) B: sin^2(x/3) C: 3sin^2(x/3)cos(x/3) D: sin^(x/3)cos(x/3)
- \( \lim \limits_{x \to 0} { { \sqrt {1 + x\sin x} - \cos x} \over { { {\sin }^2}{x \over 2}}} = \)______ 。
- 以下表达式中，有两个的计算结果是相同的，请挑选出来 A: 1 / sqrt(sin(x) * sin(x) + cos(y) * cos(y)) B: sqrt(pow(sin(x), 2) + pow(cos(y), 2)) C: pow(sin(x) * sin(x) + cos(y) * cos(y), 0.5) D: pow(pow(sin(x), 2) + pow(cos(y), 2), 2)
- 求函数$y = \root 3 \of {x + \sqrt x } $的导数$y' = $( ) A: ${{1 + 2\sqrt x } \over {\root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$ B: $ {{1 + 2\sqrt x } \over {6\root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$ C: $ {{1 + 2\sqrt x } \over {6\sqrt x \cdot \root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$ D: $ {{1 + 2\sqrt x } \over {\sqrt x \cdot \root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$