• 2022-06-09
    由[tex=3.643x1.0]Affu/7yg0q/WGkOnmrZupw==[/tex]组成双极性输出[tex=2.0x1.286]IDdrPkvhJJ/+UQMIqyyyBQ==[/tex]转换器如图题[tex=2.5x1.286]PDQUxdOFNiT2CoPN/ljXHw==[/tex]所示。根据电路写出输出电压 [tex=0.857x1.0]wNKCIalimEsZVy6seQVLKg==[/tex] 的表达式。[img=528x234]17d0ad99ffccc95.png[/img]
  • 解:  当不考虑 [tex=3.571x1.286]ACWVE3FQtHfBQMO4tuUAFtfQyuJMAdICFEOnzS1h/E8=[/tex] 支路作用时[tex=10.143x3.429]1MXOmGeBaoJcUmqNq4pl8Dnx9i3pozjpAcYo3cf2cMokCYF2ytSOcTG0WDIb1EKGOVJ+s78F7r+G6jLxc479xKU5aq6Fv+q+tmpBQEAyawx7OOlM9UG/ZGesl+L9E707[/tex]加入 [tex=3.571x1.286]ACWVE3FQtHfBQMO4tuUAFtfQyuJMAdICFEOnzS1h/E8=[/tex]后, 流入反相端的总电流[tex=10.857x3.429]zHnlzviF6m/1xWSkaGg0+iaC8+SelEuRU4bMF/Gif3mFd+mnaAt6cMgNfa6fT77tgQvViwTXNgbo4IxaxAky9+F53mKPDimmdefqTCOGE5SEZV8kdrW8Ij5v3oCM3bgUYTlTivJiLG7AN5rtXDnrrQ==[/tex]于是可得[tex=15.929x5.071]qeiYnKXLEhyhuGRg8yLtr7xx5qy10zcCeoByylYB/jKkcTylrRAWl2wzcTA+mZMxZTfvNcNSecVIfk04iKEwHKCeIQF/BQFomWndk2VD8hb7mGiSR183/DEGcmtgf3cPauwNpiA9qUToUVyeNBkFcrWRGO5Q7e141e4ksYVZOHUkdTRVm78QVog6u8x5sRHD7nM/soRm4aEBqv/wAsp1rvsnsazhFkDVcwWEOQ8EgUGGFQ1WGDDmVb+CVVcAtkoQ[/tex]当 [tex=2.643x1.286]jz9G4v3qONHdOKxaL1uq9g==[/tex]时,[tex=13.143x3.429]/IgCPRvqUgQDaCWbBg1y2sm2M7Slhnu1iNR5QqVWgZv6akDU2miTD7416mvucRB0/pKMV5w5+x4LlwF0OFB1ugRI22eFItZK7APDIco2D6ok06+b3S4T5x4UhLG3CvOsDsN4/22KMvkBJXH797PjGg==[/tex]

    内容

    • 0

      已知函数[tex=5.786x1.286]13HU85CYYmhshZKcGbB8Tw==[/tex]的卡诺图如图题[tex=2.0x1.286]6AY4zt7JxnitfK76rzCq1w==[/tex]所示,试写出函数[tex=0.714x1.286]LA74ioWWkXdGbHCtFk/Sog==[/tex]的最简与或表达式。[img=290x220]17d032b3516b312.png[/img]

    • 1

      计数型[tex=2.071x1.286]KvJGNqDfRU16Wi0AdPYL/w==[/tex]转换器如图题[tex=2.5x1.286]RdS3rgWfEkahHsSKAG/Gdg==[/tex]所示。试分析其工作原理。[img=600x352]17d0aeca6df328d.png[/img]

    • 2

      如题2-1(5)图所示电路中,[tex=1.786x1.286]zZmGYjM2/AYDi6agvCVQcQ==[/tex] 电压源单独作用于电路产生的电流 [tex=0.571x1.286]RM7SKoKhXo5BhokAgZJ3fQ==[/tex]分量应为[img=478x235]1798554c3d0b0d9.png[/img] 未知类型:{'options': ['[tex=2.0x1.286]HAngCeHKcvpYpIij78h/cg==[/tex]', '0', '[tex=2.0x1.286]IsUs5Y0SJ8ff0lSACe571w==[/tex]', '[tex=2.0x1.286]AxCMhp5QXQdhAIgz1NsYZg==[/tex]'], 'type': 102}

    • 3

      列出图题[tex=2.0x1.286]RSjRv+i3l6V4jbgaPYMlrg==[/tex]所示电路的功能表,并与表[tex=2.0x1.286]RSjRv+i3l6V4jbgaPYMlrg==[/tex]比较,证明该电路的逻辑功能与图[tex=3.286x1.286]4kUOV4B6lgufXznKYr4CHQ==[/tex]和图[tex=2.071x1.286]KmXGXyXh9TqgcMtds5lGWw==[/tex]所示的锁存器相同。与图[tex=2.071x1.286]KmXGXyXh9TqgcMtds5lGWw==[/tex]所示电路比较,图题[tex=2.0x1.286]RSjRv+i3l6V4jbgaPYMlrg==[/tex]所示电路有何优点?[img=348x211]17d08fff904fc3f.png[/img]

    • 4

      电路如图题[tex=2.071x1.286]5UPBDRBXQaMpazuWnxeaJw==[/tex]所示,假设运算放大器为理想的.当输入电压为[tex=3.5x1.286]wm1EOJeY+g0OuPqUp993wPFaPjmY80Rau+X2vIFKRUU=[/tex]时,求输出电压[tex=1.071x1.286]0x4lgrSNDR2GZMZu6ffQlw==[/tex]的值.[img=328x187]179cce6d5422d93.png[/img]