设[tex=6.214x2.786]3BT1BgBZQ5uJXxD5dg+w22yf3WUDT1WDQ/l2viCm3BlSw0/VFG6FwuGbjRI67m4CN8GHbp6r85GzIbJ5OLVycQ==[/tex]，求所有与[tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex]可交换的矩阵.
举一反三
- 设[tex=6.214x2.786]3BT1BgBZQ5uJXxD5dg+w2/ihVlt0xyldvPRdyrGXDJ03CMdD3FN35UznVSS8prhxN0E7ddqhCiX7cLDEru2Tiw==[/tex]，求与[tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex]可交换的所有矩阵.
- 求解下列矩阵对策,其中赢得矩阵 [tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex] 为$\left[\begin{array}{llll}2 & 7 & 2 & 1 \\ 2 & 2 & 3 & 4 \\ 3 & 5 & 4 & 4 \\ 2 & 3 & 1 & 6\end{array}\right]$
- 如果[tex=4.143x1.214]rf8d/F3EpGZ04p2NWMmjcQ==[/tex] 矩阵 [tex=0.786x1.0]sHo1pKm+gjxjcUAJjHrarQ==[/tex]就称为与 [tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex] 可交换.设[tex=6.214x2.786]3BT1BgBZQ5uJXxD5dg+w22FN1OssYWb3uPRmaaEM3N86dew3GmbZZdCp0h0qrpZ7PK/rtLLovnW0/6JQcAYokQ==[/tex]求所有与 [tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex]可交换的矩阵.
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']