举一反三
- 证明下列不等式:[tex=12.714x1.286]Kit/PExCOWnfuERcxfvK4NChO9vvbtLdKmq0bT1U54/fckg4nbRH2cnZMa7jqB1o[/tex]
- 证明:不等式[tex=4.143x1.143]V1cMVpAPlZC/oEIH8POnKKkri2N/1cnaxqDWfusMqZA=[/tex],等式仅在[tex=1.857x1.0]3eSlq+W5GTl4xGu7dhqzgw==[/tex]时成立.
- 证明下列不等式:当x>0时,[tex=5.571x1.357]yPiUK5s9KWIySs4Vo4NOaA==[/tex]
- 证明下列不等式:当x>1时,[tex=5.571x2.357]cu8b01R+7uITdLa6NsPEW6TmtQGeN2pfZxFE3bC0pvs=[/tex]
- 已知 x = [6, 9, 8],那么执行语句 x.insert(0, 1)之后,x的值为( )。 A: [1, 6, 9, 8] B: [6, 9, 8, 1] C: [6, 9, 1, 8] D: [6, 1, 9, 8]
内容
- 0
>>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 1
set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 2
设 [tex=4.071x1.286]nR/cJv6OqBZsTDNk+MpaBw==[/tex],证明不等式[p=align:center][tex=12.0x2.286]X/Ri20XB58Oz2ZfZYw8yP6qEPtmDovjJXhp8eOv8KNGfaJgnC6X1XEJ+2xzOJGQkwqKgHtAAyzdujVIOGdlO7gycABMU66WddDs30mp1D7k=[/tex]。(本题满分8分)
- 3
【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 4
设[tex=0.929x1.286]uswT/CEcOIwMpCvTz/zeaA==[/tex]是一随机变量,[tex=1.214x1.286]ywJhPpsrK/zutVlpmSO1aw==[/tex]为任意实数,[tex=1.714x1.286]p+zOLBbKURbVjWbmuQcavg==[/tex]为[tex=0.929x1.286]uswT/CEcOIwMpCvTz/zeaA==[/tex]的数学期望,则有[input=type:blank,size:6][/input] . 未知类型:{'options': ['[tex=12.429x1.286]q8HyMzYbNdS1m5JUH9I4P2hQkYCLaYrqtxCkFw7B/sNfba/3vR/wvSOSMJOWk78q[/tex]', '[tex=12.429x1.286]q8HyMzYbNdS1m5JUH9I4P2ulDzbX1WJGk5hIN2LNVZWDlNVuxPvZEsiV3Cup+6g7[/tex]', '[tex=12.429x1.286]q8HyMzYbNdS1m5JUH9I4P43nhMlotD7qMdvbP2wr7qcU8ZwIGcFbGu9PHX0MceTbQAQjho10ZtEiYsmPIVEROw==[/tex]', '[tex=7.214x1.286]q8HyMzYbNdS1m5JUH9I4P7W9T0H0r3AUr6X06QcrlSNOXiTxR1DoUbzN1GIHu6tj[/tex]'], 'type': 102}