In order to determine the slope and displacement of a beam by integration, it is important to use the proper signs for M, V or w. Positive deflection v is ( ) and as a result, the positive slope angle [img=9x19]17de8338539dd00.png[/img] will be measured ( ) from the [img=11x14]17de83385e83d59.png[/img] is positive to the ( ).
A: upward, counterclockwise, right
B: upward, counterclockwise, left
C: downward, clockwise, right
D: upward, clockwise, left
A: upward, counterclockwise, right
B: upward, counterclockwise, left
C: downward, clockwise, right
D: upward, clockwise, left
举一反三
- In the following cantilever beam, the ( ) of the cross-section C and B is different.[img=617x199]1803a0fa75c83b4.jpg[/img] A: bending moment M B: shear force V C: deflection v D: slope angle [img=9x19]1803a0fa7e46ed5.png[/img]
- Given: function[img=34x25]17de81e321f7032.png[/img] has a second-order derivative within the interval of [img=8x19]17de81e32caa1a1.png[/img], and . Then, within the interval of , the curve is: A: increasing and convex upward B: decreasing and convex upward C: increasing and convex downward D: decreasing and convex downward
- The English keep the fork in the left hand, with the point turned up or downward? A: upward B: downward
- In the following cantilever beam, the ( ) of the cross-section C and B is different.[img=540x190]1803a365910cafa.png[/img] A: Slope angle θ； B: Shear force Fs; C: Deflection y; D: Bending moment M.
- 设\(z = {e^u}\sin v,\;u = xy,\;v = x + y\)，则\( { { \partial z} \over {\partial y}}=\)( ) A: \(x{e^{xy}}\sin \left( {x + y} \right) + {e^{xy}}\cos \left( {x + y} \right)\) B: \(x{e^{xy}}\sin \left( {x + y} \right) \) C: \( {e^{xy}}\cos \left( {x + y} \right)\) D: \(x{e^{xy}}\sin \left( {x + y} \right) - {e^{xy}}\cos \left( {x + y} \right)\)