• 2022-06-07
    已知u=10sin(314t-[img=8x11]17e435c54b0e71f.jpg[/img]/3)V,i=10[img=21x20]17e43630963ca84.jpg[/img]sin(314t+[img=8x11]17e435c54b0e71f.jpg[/img]/2)A,电压与电流的相位差[img=45x16]17e447252d78810.jpg[/img]是( )度,即( )超前( ).
  • 17e445e8c592ee2.jpg;[img=31x34]17e44725387fa68.jpg[/img];-[img=27x17]17e447254339968.jpg[/img];-150°;-150#电流#电压

    内容

    • 0

      求微分方程[img=143x21]17da5f14490e50e.png[/img]的通解,实验命令为(). A: dsolve(D2y-2*Dy+5*y=sin(2*x),x)ans =exp(x)*sin(2*x)*C2+exp(x)*cos(2*x)*C1+1/17*sin(2*x)+4/17*cos(2*x) B: dsolve('D2y-2*Dy+5*y=sin(2*x)','x')ans =cos(2*x)*(sin(4*x)/17 - cos(4*x)/68 + 1/4) - sin(2*x)*(cos(4*x)/17 + sin(4*x)/68) + C1*cos(2*x)*exp(x) - C2*sin(2*x)*exp(x) C: dsolve(D2y-2*Dy+5*y=sin(2*x),'x','y')ans =exp(x)*sin(2*x)*C2+exp(x)*cos(2*x)*C1+1/17*sin(2*x)+4/17*cos(2*x)

    • 1

      设随机变量(X,Y)在区域{(x,y): 0<|y|< x <2}内均匀分布,则以下结果正确的是 A: 当0<x<2时,[img=96x25]1802dded7db6eef.png[/img]. B: E(X)=4/3 C: 当0<|y|<2时,[img=105x45]1802dded872b92f.png[/img]. D: P(X<1)=0.5 E: 当0<x<2时,[img=110x45]1802dded915de6e.png[/img]. F: E(X)=2/3 G: 当0<y<2时,[img=95x43]1802dded9a54300.png[/img].

    • 2

      已知u=220[img=17x21]17e447876c08e89.png[/img]sin(ωt+530)V,i=50[img=17x21]17e447876c08e89.png[/img]sin(ωt-370)A,则电压与电流的相位差是____度。说明电压____(超前或滞后)电流。

    • 3

      函数[img=103x33]17e0b09051e076c.jpg[/img]的反函数是 未知类型:{'options': ['y=1-3cosx,x[img=6x11]17e0b0905fe87f4.jpg[/img]&#91;0,[img=8x11]17e0a7285a871a0.jpg[/img]&#93;', ' y=1+3cosx,x[img=6x11]17e0b0905fe87f4.jpg[/img]&#91;0,[img=8x11]17e0a7285a871a0.jpg[/img]&#93;', ' y=1-3sinx,x[img=6x11]17e0b0905fe87f4.jpg[/img]&#91;0,[img=8x11]17e0a7285a871a0.jpg[/img]&#93;', ' y=1+3sinx,x[img=6x11]17e0b0905fe87f4.jpg[/img]&#91;0,[img=8x11]17e0a7285a871a0.jpg[/img]&#93;'], 'type': 102}

    • 4

      已知正弦电压的振幅为10V,周期为100ms,初相位π/6为。试写出正弦量的函数表达式 未知类型:{'options': ['10sin(62.8t+[img=20x15]17e436158120103.jpg[/img])', ' 10[img=21x20]17e43630963ca84.jpg[/img]sin(62.8t+[img=20x15]17e436158120103.jpg[/img])', ' 10[img=21x20]17e43630963ca84.jpg[/img]sin(62.8t+[img=20x15]17e43aa0991ff38.jpg[/img])', ' 10cos(62.8t+[img=20x15]17e436158120103.jpg[/img])'], 'type': 102}