设函数[tex=3.143x1.357]Eg6rSgUNTUffRvxyTlFbYQ==[/tex]在点[tex=0.571x0.786]c5VsltFnl9nO0qB/vNKOWA==[/tex]二阶可导，且[tex=4.071x1.429]U93ae75fuTDIyESpUsh0Znxw8HsPs/3+dKg1A7Sgz2g=[/tex].若[tex=1.857x1.357]BGkv0wKMIn2R4tUsMDFEFA==[/tex]存在反函数[tex=4.214x1.5]X4tnRmg9ptWcXRsWJCIE5iFzaBn0AyeVAzDEO7/ylT4=[/tex]，试用[tex=5.0x1.429]U93ae75fuTDIyESpUsh0Zvaxe9NteqcymEPLd1HF4oN74xhsC9JoCG9xIxr00sj6[/tex]以及[tex=2.571x1.429]o1NxfHFvh4pfuP8b7Vf/BLM9mw2a8g13iR+liT0iBJOcTMG5+16J5Iuai7VsI2ee[/tex]表示[tex=4.5x1.643]WfldAP4jTSnBM8Wh+uruUgZBFwSP/ENp0INsrcYyk4n+zScHyfcxFyF9NLgREvygC08tq3NgLA4OzAsJJnzXqg==[/tex]
举一反三
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 若要将一个长度为N=16的序列x(n)重新位倒序,作为某一FFT算法的输入,则位倒序后序列的样本序号为( )。 A: x(15), x(14), x(13), x(12), x(11), x(10), x(9), x(8), x(7), x(6),<br/>x(5), x(4), x(3), x(2), x(1), x(0) B: x(0), x(4), x(2), x(6), x(1), x(5), x(3), x(7), x(8), x(12), x(10),<br/>x(14), x(9), x(13), x(11), x(15) C: x(0), x(2), x(4), x(6), x(8), x(10), x(12), x(14), x(1), x(3), x(5),<br/>x(7), x(9), x(11), x(13), x(15) D: x(0), x(8), x(4), x(12), x(2), x(10), x(6), x(14), x(1), x(9), x(5),<br/>x(13), x(3), x(11), x(7), x(15)
- 设DES加密算法中的一个S盒为： 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 0 1 2 3 14 4 13 1 2 15 11 8 3 10 6 12 5 9 0 7 0 15 7 4 14 2 13 1 10 6 12 11 9 5 3 8 4 1 14 8 13 6 2 11 15 12 9 7 3 10 5 0 15 12 8 2 4 9 1 7 5 11 A: 1010 B: 0001 C: 1011 D: 0111