(1)已知k、n∈N*,且k≤n,求证:kCkn=nCk-1n-1;
(1)已知k、n∈N*,且k≤n,求证:kCkn=nCk-1n-1;
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(1)已知k、n∈N*,且k≤n,求证:kCkn=nCk-1n-1;