已知某汉字的区位码是1221,则其国标码是:

2011年，我国城镇新增就业（）万人。 A: 1000 B: 1121 C: 1221

图中所绘的FM 乙1221 的开启方向为

以下字符串中，是回文字符串的是（）。 A: abcba B: 12321 C: 1221 D: abcdef

中车建工“十四五”规划可概括为（） A: “1127” B: “1221” C: “13579”

下面代码的执行结果是： ls = [“2020”, “2020”, “Python”] ls.append(2020) ls.append([2020, “2020”]) print(ls): [‘2020’, ‘2020’, ‘Python’, 2020, 2020, ‘2020’]|[‘2020’, ‘2020’, ‘Python’, 2020, [2020, ‘2020’]]|[‘2020’, ‘2020’, ‘Python’, 2020, [‘2020’]]|[‘2020’, ‘2020’, ‘Python’, 2020]

下面代码的执行结果是‪‬‪‬‪‬‪‬‪‬‮‬‫‬‭‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‪‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‪‬‪‬( )‪‬‪‬‪‬‪‬‪‬‮‬‫‬‭‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‪‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‪‬‪‬ ‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬。ls = ["2020", "20.20", "Python"] ls.append(2020)ls.append([2020, "2020"])print(ls) A: ['2020', '20.20', 'Python', 2020, 2020, '2020'] B: ['2020', '20.20', 'Python', 2020, [2020, '2020']] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, ['2020']]

下面代码的执行结果是：‪‪‪‪‪‪‫‪‪‪‪‪‪‫‪‪‪‪‪‫‪‪‪‪‪‫‪‪‪‪‪‪‫‪‪‪‪‪‪‫ ls = ["2020", "20.20", "Python"] ls.append(2020) ls.append([2020, "2020"]) print(ls) A: ['2020', '20.20', 'Python', 2020, ['2020']] B: ['2020', '20.20', 'Python', 2020, 2020, '2020'] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, [2020, '2020']]

以下代码的输出结果是______。ls = ["2020", "20.20", "Python"]ls.append(2020)ls.append([2020, "2020"])print(ls) A: ['2020', '20.20', 'Python', 2020] B: ['2020', '20.20', 'Python', 2020, [2020, '2020']] C: ['2020', '20.20', 'Python', 2020, 2020, '2020'] D: ['2020', '20.20', 'Python', 2020, ['2020']]

下面代码的执行结果是：（ ）ls= [“2020”, “20.20”, “Python”]ls.append(2020)ls.append([2020, “2020”])print(ls) A: [‘2020’, ‘20.20’, ‘Python’, 2020] B: [‘2020’, ‘20.20’, ‘Python’, 2020, [2020, ‘2020’]] C: [‘2020’, ‘20.20’, ‘Python’, 2020, [‘2020’]] D: [‘2020’, ‘20.20’, ‘Python’, 2020, 2020, ‘2020’]r