价格无差异曲线和效用无差异曲线类似，横轴和纵轴分别对应[tex=1.071x1.214]HydHJF/kXn6Hho1N1HZ7uA==[/tex]和[tex=1.0x1.286]j1kFrkz5OMSt5Q7Dy/8YCw==[/tex]，其一般形式为:[br][/br][tex=10.429x1.357]BpZf3QaUQjI/JgaX1MNHkE/ZKBaydLLd/MyYZ7jkm0QDxzfLHTjEs12e7st0eiQfv5eZTasjfFv+H2FDaw8+hS56GAHVINhNvQLFN/uYMb4=[/tex][img=510x372]17ca2eee6fc1394.png[/img]观察无差异曲线的斜率,你得到了什么?

价格无差异曲线和效用无差异曲线类似，横轴和纵轴分别对应[tex=1.071x1.214]HydHJF/kXn6Hho1N1HZ7uA==[/tex]和[tex=1.0x1.286]j1kFrkz5OMSt5Q7Dy/8YCw==[/tex]，其一般形式为:[br][/br][tex=10.429x1.357]BpZf3QaUQjI/JgaX1MNHkE/ZKBaydLLd/MyYZ7jkm0QDxzfLHTjEs12e7st0eiQfv5eZTasjfFv+H2FDaw8+hS56GAHVINhNvQLFN/uYMb4=[/tex][img=510x372]17ca2eee6fc1394.png[/img]在无差异曲线图中，如何表示效用增加的方向?

价格无差异曲线和效用无差异曲线类似，横轴和纵轴分别对应[tex=1.071x1.214]HydHJF/kXn6Hho1N1HZ7uA==[/tex]和[tex=1.0x1.286]j1kFrkz5OMSt5Q7Dy/8YCw==[/tex]，其一般形式为:[br][/br][tex=10.429x1.357]BpZf3QaUQjI/JgaX1MNHkE/ZKBaydLLd/MyYZ7jkm0QDxzfLHTjEs12e7st0eiQfv5eZTasjfFv+H2FDaw8+hS56GAHVINhNvQLFN/uYMb4=[/tex]写出[tex=4.071x1.214]DaihuY64IhFSPsOn8DVRvg==[/tex]的柯布一道格拉斯情形下的函数形式，并画出一条无差异曲线。

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是（）。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

请仔细观察下面行列式的计算过程，如果四个等号都理解了，请选择A，否则请选择B。 | a 1 1 1 1 | |a＋4 a＋4 a＋4 a＋4 a＋4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a＋4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a＋4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a＋4)(a–1)^4

共有4个站进行码分多址通信。4个站的码片序列为：a：（-1 -1 -1 +1 +1 -1 +1 +1） b：（-1 -1 +1 -1 +1 +1 +1 -1） c：（-1 +1 -1 +1 +1 +1 -1 -1） d：（-1 +1 -1 -1 -1 -1 +1 -1） 现收到这样的码片序列：（-1 +1 -3 +1 -1 -3 +1 +1），则（ ）发送1。

共有四个站进行CDMA通信，现收到这样的码片序列（-3 +1 -1 -1 +1 +1 +1 -3），则下列站点发送了数据1的是（ ） A: （-1 -1 -1 +1 +1 -1 +1 +1） B: （-1 -1 +1 -1 +1 +1 +1 -1） C: （-1 +1 -1 +1 +1 +1 -1 -1） D: （-1 +1 -1 -1 -1 -1 +1 -1）