If the DNA strand shown below is used as a template for RNA polymerase, what would be the sequence of the resultant mRNA following transcription? 5'-CATTCCATAGCATGT-3' A: 5'-UGUACGAUACCUUAC-3' B: 5'-CAUUCCAUAGCAUGU-3' C: 5'-GUAAGGUAUCGUACA-3' D: 5'-ACAUGCUAUGGAAUG-3'
If the DNA strand shown below is used as a template for RNA polymerase, what would be the sequence of the resultant mRNA following transcription? 5'-CATTCCATAGCATGT-3' A: 5'-UGUACGAUACCUUAC-3' B: 5'-CAUUCCAUAGCAUGU-3' C: 5'-GUAAGGUAUCGUACA-3' D: 5'-ACAUGCUAUGGAAUG-3'
如果使用如下所示的DNA链RNA聚合酶作为模板,合成的序列是什么mRNA转录后? 5“-CATTCCATAGCATGT-3” A: 5'-ACAUGCUAUGGAAUG-3' B: 5'-CAUUCCAUAGCAUGU-3' C: 5'-GUAAGGUAUCGUACA-3' D: 5'-UGUACGAUACCUUAC-3'
如果使用如下所示的DNA链RNA聚合酶作为模板,合成的序列是什么mRNA转录后? 5“-CATTCCATAGCATGT-3” A: 5'-ACAUGCUAUGGAAUG-3' B: 5'-CAUUCCAUAGCAUGU-3' C: 5'-GUAAGGUAUCGUACA-3' D: 5'-UGUACGAUACCUUAC-3'
函数的定义域是/ananas/latex/p/1132315: (-∞, -3)∪(-3, +∞)|(-∞, -3)∪(-3, 3)∪(3, +∞)|(-∞, -3)∪(3, +∞)|(-∞, 3)∪(3, +∞)
函数的定义域是/ananas/latex/p/1132315: (-∞, -3)∪(-3, +∞)|(-∞, -3)∪(-3, 3)∪(3, +∞)|(-∞, -3)∪(3, +∞)|(-∞, 3)∪(3, +∞)
智慧职教: 按自然数的乘法按定义计算3×5. 解 由定义5知3x5=(3x4) 3 =[(3x3) 3] 3 ={[(3x2) 3] 3} 3 ={{[(3x1) 3] 3} 3} 3 ={{[(3 3) 3] 3} 3} ={[(6 3) 3] 3} =(9 3) 3 =12 3=15 上述计算是( )的
智慧职教: 按自然数的乘法按定义计算3×5. 解 由定义5知3x5=(3x4) 3 =[(3x3) 3] 3 ={[(3x2) 3] 3} 3 ={{[(3x1) 3] 3} 3} 3 ={{[(3 3) 3] 3} 3} ={[(6 3) 3] 3} =(9 3) 3 =12 3=15 上述计算是( )的
3√3—/3√3/
3√3—/3√3/
下列各项中,哪一项不是Kirsch边缘检测中构建的模板() A: [5 5 5;-3 0 -3;-3 -3 -3] B: [-3 5 5;-3 0 5;-3 -3 -3] C: [5 5 5;-3 -3 0;-3 -3 -3] D: [-3 -3 -3;-3 0 -3;5 5 5]
下列各项中,哪一项不是Kirsch边缘检测中构建的模板() A: [5 5 5;-3 0 -3;-3 -3 -3] B: [-3 5 5;-3 0 5;-3 -3 -3] C: [5 5 5;-3 -3 0;-3 -3 -3] D: [-3 -3 -3;-3 0 -3;5 5 5]
3⊥3与3┬3舌轴嵴形态的区别是() A: 舌轴嵴3┬3与3┬3同样明显 B: 舌轴嵴3┬3不如3⊥3明显 C: 舌轴嵴3┬3比3⊥3明显 D: 舌轴嵴3┬3与3⊥3均不明显
3⊥3与3┬3舌轴嵴形态的区别是() A: 舌轴嵴3┬3与3┬3同样明显 B: 舌轴嵴3┬3不如3⊥3明显 C: 舌轴嵴3┬3比3⊥3明显 D: 舌轴嵴3┬3与3⊥3均不明显
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第 31 题 11/3 , 7/3 , 1, , -5/3 A.7/3 B.-1/3 C.5/3 D.4/3
第 31 题 11/3 , 7/3 , 1, , -5/3 A.7/3 B.-1/3 C.5/3 D.4/3
与集合{x||x|=3}相等的集合为 A: {3} B: {-3) C: 3,-3 D: {3,-3}
与集合{x||x|=3}相等的集合为 A: {3} B: {-3) C: 3,-3 D: {3,-3}