Traffic flow of ( ) is in a completely free flow state. A: LOSⅠ B: LOSⅡ C: LOS Ⅲ D: LOS Ⅳ
Traffic flow of ( ) is in a completely free flow state. A: LOSⅠ B: LOSⅡ C: LOS Ⅲ D: LOS Ⅳ
The passage is mainly about (). A: the construction of parking spaces in Los Angeles B: the new growth pattern of the city of Los Angeles C: the public transportation system in Los Angeles D: the problem of traffic jams iii Los Angeles
The passage is mainly about (). A: the construction of parking spaces in Los Angeles B: the new growth pattern of the city of Los Angeles C: the public transportation system in Los Angeles D: the problem of traffic jams iii Los Angeles
Los chicos con los que salgo en la foto son mis compañeros de clase.
Los chicos con los que salgo en la foto son mis compañeros de clase.
向量组\(\left( {\matrix{ { - 1} \cr 3 \cr 1 \cr } } \right),\left( {\matrix{ 2 \cr 1 \cr 0 \cr } } \right),\left( {\matrix{ 1 \cr 4 \cr 1 \cr } } \right) \)线性相关.
向量组\(\left( {\matrix{ { - 1} \cr 3 \cr 1 \cr } } \right),\left( {\matrix{ 2 \cr 1 \cr 0 \cr } } \right),\left( {\matrix{ 1 \cr 4 \cr 1 \cr } } \right) \)线性相关.
¿Son cuatro los profesores?
¿Son cuatro los profesores?
Hollywood is located in ______. A: Los Angeles, California B: San Francisco, California C: Chicago, Illinois D: Los Vegas, Nevada
Hollywood is located in ______. A: Los Angeles, California B: San Francisco, California C: Chicago, Illinois D: Los Vegas, Nevada
19. A) In Beijing.B) In London.C)In New York.D) In Los Angeles A: In Beijing. B: In London. C: In New York. D: In Los Angeles
19. A) In Beijing.B) In London.C)In New York.D) In Los Angeles A: In Beijing. B: In London. C: In New York. D: In Los Angeles
使用条件电势和标准电极电势计算Cr2O72-/Cr3+的电极电势,下列公式正确的是(Cr(VI)表示Cr2O72-;Cr(III)表示Cr3+): A: E Cr(VI)/ Cr(III)= EƟ' Cr(VI)/ Cr(III)+(0.0592/6)*lg(C Cr(VI)/ C Cr(III) B: E Cr(VI)/ Cr(III)= EƟ' Cr(VI)/ Cr(III)+ (0.0592/6)*lg(C Cr(VI)/ C2 Cr(III) C: E Cr(VI)/ Cr(III)= EƟ' Cr(VI)/ Cr(III)+ (0.0592/6)*lg(C Cr(VI)[H+]14/ C2 Cr(III) D: ECr(VI)/ Cr(III)=EƟCr(VI)/Cr(III)+ (0.0592/6)*lg([Cr(VI)][H+]14/ [Cr(III)2])
使用条件电势和标准电极电势计算Cr2O72-/Cr3+的电极电势,下列公式正确的是(Cr(VI)表示Cr2O72-;Cr(III)表示Cr3+): A: E Cr(VI)/ Cr(III)= EƟ' Cr(VI)/ Cr(III)+(0.0592/6)*lg(C Cr(VI)/ C Cr(III) B: E Cr(VI)/ Cr(III)= EƟ' Cr(VI)/ Cr(III)+ (0.0592/6)*lg(C Cr(VI)/ C2 Cr(III) C: E Cr(VI)/ Cr(III)= EƟ' Cr(VI)/ Cr(III)+ (0.0592/6)*lg(C Cr(VI)[H+]14/ C2 Cr(III) D: ECr(VI)/ Cr(III)=EƟCr(VI)/Cr(III)+ (0.0592/6)*lg([Cr(VI)][H+]14/ [Cr(III)2])
设矩阵\(A = \left( {\matrix{ \matrix{ x \cr 0 \cr y \cr} & \matrix{ 0 \cr 2 \cr 0 \cr} & \matrix{ y \cr 0 \cr - 2 \cr} \cr } } \right)\)的一个特征值为\(-3\),且\(A\)的三个特征值之积为\(-12\),则\(x =\)______
设矩阵\(A = \left( {\matrix{ \matrix{ x \cr 0 \cr y \cr} & \matrix{ 0 \cr 2 \cr 0 \cr} & \matrix{ y \cr 0 \cr - 2 \cr} \cr } } \right)\)的一个特征值为\(-3\),且\(A\)的三个特征值之积为\(-12\),则\(x =\)______
以下语句的输出结果是()(<CR>为回车,Δ表示空格)a="Beijing"<CR>b="ShangHai"<CR>Printa;b<CR> A: ABeijing<CR>ShangHai B: B<CR>beijing<CR>ShangHai C: CBeijingShangHai<CR> D: DΔBeijingΔ
以下语句的输出结果是()(<CR>为回车,Δ表示空格)a="Beijing"<CR>b="ShangHai"<CR>Printa;b<CR> A: ABeijing<CR>ShangHai B: B<CR>beijing<CR>ShangHai C: CBeijingShangHai<CR> D: DΔBeijingΔ