• 2022-06-04 问题

    下面代码的输出结果是__________。letter=['A','B','C','D','D','D']foriinletter:ifi=='D':letter.remove(i)print(letter) A: ['A','B','C'] B: ['A','B','C','D','D'] C: ['A','B','C','D','D','D'] D: ['A','B','C','D']

    下面代码的输出结果是__________。letter=['A','B','C','D','D','D']foriinletter:ifi=='D':letter.remove(i)print(letter) A: ['A','B','C'] B: ['A','B','C','D','D'] C: ['A','B','C','D','D','D'] D: ['A','B','C','D']

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