以下程序段实现的输出是（）。for(i=0;i<;=9;i++)s[i]=i;for(i=9;i>;=0;i--)printf("%2d",s[i]);[/i][/i] A: 9 7 5 3 1 B: 1 3 5 7 9 C: 9 8 7 6 5 4 3 2 1 0 D: 0 1 2 3 4 5 6 7 8 9

Given generating function $G(x)=\frac{3+78x}{1-3x-54x^2}$, find the corresponding sequence $\{a_n\}$ A: $\{a_n\}=7*(-9)^n+4*6^n$ B: $\{a_n\}=7*9^n-4*6^n$ C: $\{a_n\}=7*9^n-4*(-6)^n$ D: $\{a_n\}=7*(-9)^n-4*6^n$ E: $\{a_n\}=7*(-9)^n+4*(-6)^n$ F: $\{a_n\}=7*(-9)^n-4*(-6)^n$

【单选题】#include<stdio.h>intmain(){inta[3][3],*p,i;p=&a[0][0];for(i=0;i<9;i++){p[i]=i+1;}printf("%d ",a[1][2]);return0;} A. 6 B. 3 C. 9 D. 2

【单选题】以下程序的输出结果是: void main() { int i,j,n,a[5]={3,4,1,2,-6}; for(i=0;i<5;i++) for(j=i+1;j<5;j++) if(a[j]<a[i]) { n=a[j];a[j]=a[i];a[i]=n; } for(i=0;i<5;i++) printf("%3d",a[i]); printf(" "); } A. 3 4 1 2 -6 B. 4 3 2 1 -6 C. -6 1 2 3 4 D. 4321-6

在以下字符串String的赋值运算中，错误的是( )。? char str[]= { 'S' ,'t', 'r' ,'i','n', 'g',0};|char str[10]= { 'S' ,'t', 'r' ,'i','n', 'g','\0'};|char str[6]= { 'S' ,'t', 'r' ,'i','n', 'g'};|char str[10]= "String";

Grammer G&#91;&#93;= ( {b} , {N , B} , N , {N→b│ bB , B→bN} ), The language described in this grammar is (). A: L(G[N])={bi│<br/>i ≥ 0} B: L(G[N])={b2i│<br/>i≥ 0} C: L(G[N])={b2i+1│<br/>i ≥ 0} D: L(G[N])={b2i+1│<br/>i ≥ 1}

for (int i = 1; i <= 10; i++){ if (i % 5 != 0) continue; Console.WriteLine("{0}", i); }该段程序执行后输出_____。 A: 5 10 B: 1 2 3 4 6 7 8 9 C: 5 D: 1 2 3 4 5 6 7 8 9 10

以下程序的输出是 ___。main() {char a[2][5]={”6937”,”8254”}; int i,j,s=0; for ( i = 0; i < 2; i++ ) for ( j = 0; a[i][j]>’0’ && a[i][j]<=’9’; j+=2 ) s=10*s+a[i][j]-’0’; printf(”s=%d\n”,s);}

设X ~ N(2, 9)则Y = (X – 2 )/9 ~ N(0, 1).

执行下面的初始化语句，( )保存的不是字符串。 A: char str[10]= { 'S' ,'t', 'r' ,'i','n', 'g','\0'}; B: char str[10]= "String"; C: char str[6]= { 'S' ,'t', 'r' ,'i','n', 'g'}; D: char str[]= { 'S' ,'t', 'r' ,'i','n', 'g',0};