下列程序编译并运行的结果为()publicclassTest{publicstaticvoidmain(String[]args){try{inti=1;System.out.println(i++);}finally{System.out.println(++i);}}}

请阅读下面的程序，sum的值为（）publicclassTest{publicstaticvoidmain(String[]args){intsum=0;for(inti=1;i=100;i++){if(i%2==1){continue;}sum+=i;}System.out.println(sum=+sum);}}

下列哪个选项的java源文件代码片段是不正确的? A: packagetestpackage；publicclassTest{} B: importjava.io.*；packagetestpaekage；publicclassTest{} C: importjava.io.*；classPerson{}publicclassTest{} D: importjava.io.*；importjava.awt.*；publicclassTest{}

分析以下代码:publicclassTest{publicstaticvoidmain(String[]args){int[]a=newint[4];a[1]=1;a=newint[2];System.out.println("a[1]is"+a[1]);}} A: 程序有一个编译错误,因为newint[2]被分配给了。 B: 程序有一个运行时错误,因为[1]未初始化。 C: 程序显示a[1]is0。 D: 程序显示a[1]is1。

下面代码运行结果是（）。publicclassTest{publicstaticvoidmain(String[]args){int[]a=newint[3];int[]b=newint[]{1,2,3,4,5};a=b;for(inti=0;i<=b.length;i++){System.out.print(a[i]+ " "); }}}[/i] A: 1 2 3 4 B: 1 2 3 C: 0 1 2 3 4 D: 数组越界异常

设有如下程序publicclasstest{publicstaticvoidmain(Stringargs[]){IntegerintObj=Integer.valueOf(args[args.length-1]);inti=intObj.intValue();if(args.length>1) System.out.println(i);if(args.length>0) System.out.println(i-1);elseSystem.out.println(i-2);}}运行程序,输入如下命令

以下代码的输出结果是（）。publicclassTest{publicstaticvoidmain(String[]args){double[]price=newdouble[5];price[0]=98.10;price[1]=32.18;price[2]=77.75;System.out.print((int)price[0]+""+(int)price[1]+""+(int)price[2]+""+(int)price[3]+""+(int)price[4]);}}

类Test1定义如下： 1．publicclassTest1{ 2．publicfloataMethod（floata，floatb）{} 3． 4．} 将以下哪种方法插入行3是不合法的。

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1