• 2022-06-27 问题

    下列代码描述中,不能产生时序逻辑的( ) A: always (*)begainif (a&b) rega=c;elserega=0;end B: always (*)begainif (a&b) rega=c;y=rega;end C: always @(a)begainCase(a)2’b00: out=4’b0001;2’b01: out=4’b0010; 2’b10: out=4’b0100;endcaseend

    下列代码描述中,不能产生时序逻辑的( ) A: always (*)begainif (a&b) rega=c;elserega=0;end B: always (*)begainif (a&b) rega=c;y=rega;end C: always @(a)begainCase(a)2’b00: out=4’b0001;2’b01: out=4’b0010; 2’b10: out=4’b0100;endcaseend

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