You must complete both tasks to get an accurate band score.

You can do well in one writing task to get a good score.

Writing Task 2 counts more towards your overall test band score.

下面代码的输出结果是()。 <?php $score=87; if($score>=90 && $score<=100){$grade="优秀";} if($score>=80){$grade="良好";} if($score>=70){$grade="一般";} if($score>=60){$grade="及格";} else{$grade="不及格";} echo $grade; ?>

以下参数传递正确的是： A: def score(mid_score, end_score): ……score(88, 79) B: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(88, 79) C: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(end_score = 79, mid_score = 88) D: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(mid_score = 88, end_score = 79,0.5)

There are ________students playing basketball in the room. A: score of B: scores of C: two score D: two score of

若有定义int score&#91;10&#93;;，则对score数组中的元素的正确引用是（ ） A: score[10] B: score[6.0] C: score[0] D: score(7)

从学生成绩表SC中查询平均成绩大于60分的同学的学号和平均成绩的正确语句为： A: selectsno,avg(score)assscorefromscgroupbysnohavingavg(score)>60 B: selectsno,avg(score)assscorefromscgroupbysnowhereavg(score)>60 C: selectsno,avg(score)assscorefromscwhereavg(score)>60 D: selectsno,avg(score)assscorefromschavingavg(score)>60

查询成绩在60-80之间的学生信息，正确的语句是？ A: db.students.find({"score":{$gte:60,$lte:80}}) B: db.students.find({"score":{$gte:80},{"score":{$lte:60}}}) C: db.students.find({"score":{$gte:60},{"score":{$te:80}}}) D: db.students.find({"score":{$gt:80},{"score":{$lt:60}}})

Jed had an exam score of 50 percentage points. There is an extra credit assignment that Jed can complete that will raise his exam score by 20 percentage points. Jed has determined that the extra credit assignment will take 10 hours of his time. Jed will complete the assignment he values the A: 20 percentage points more than the 10 hours of his time. B: 10 hours of his time more than the 20 percentage points. C: 70 percentage points more than the 10 hours of his time. D: wants a higher score.