下列哪项属于肾功能不全的衰竭期（   ） 未知类型：{'options': ['[tex=23.857x1.357]84XcHeDxTZJno3BVgyvGO8AJvtCztiedN2HJqp2hA3779vCTLwckLVzll5iFcdKmKgLGaTsSdAugu4r7ucdqCH/Wtbz1OKuozRvodEgDAtP/SHaFX0yL0qlCEcmhvAwpS+/66eOHiFkMT6Tp4OP7IGMQH/65dhs8cZvlff6KAYvusTEvI1c7fb/bfMxGQ/cv[/tex]', '[tex=25.0x1.357]oU+F/zzYPksjZF/k2XWESycnEtuCqdmz5Ff+kOIxMIsDSwsPr2H+V1/PCJhssOmUl2/i8G0+vuPRkz3u8hEY3iy6Bpl5HK8VnCO/vdX1Ow6M4BI2EnGgnYjvQdOem6cVqDaEc/QsCt+f/wbpu1JkzicMO02N0Z334zX8wziUncs7cypqRF05lXfIRhNIsO5V[/tex]', '[tex=25.357x1.357]gYWLhrL9rueDE0QI03ICLxVtowOLKtvngOyHPvOerNTgT9nsxNeK7mveUKeqQRthmvqVxfVDW49RpQoBye9oNh0pT5YOpWQIQ6GlGu1P6dTluKInb7kodiYLWJqse3/SJ5IgEpTfwAz/wYpOkuA7eQ5zoUj7ZPuchWSDF6vcm5c=[/tex]', '[tex=24.857x1.357]XoFH4zYL4FWwm2npyyKB6KMTdcJe1YEwuAlDmagbsVXaDGuAXhM9JcnukhuEADeh4UENVgJGdZ7tv/iS0OerLA/e577IDzjYU540UOfR4pKtJhIfky6IA9DQd0/dyq0yA1rDKgFexIQJeFz9H9n7sgK+xAEiyzgFg1Vpu7VClT6csOWqg+46Z72+ecEFobH2[/tex]', '[tex=24.357x1.357]gYWLhrL9rueDE0QI03ICLxVtowOLKtvngOyHPvOerNTgT9nsxNeK7mveUKeqQRthq9NflGxfe24wnZaCVXDrATcjDl8zVcazTVyyOeJn7kmRc6HN7RMOAadj6Bh3nwExPHJAMGoTdFn68JSO7W27oeQevwWBc+rG6H0+MktsfQ8tvAtfnNnp9tZRvRsjifQF[/tex]'], 'type': 102}

【单选题】NO 2 、NO 2 - 、NO 2 + 键角大小关系正确的是 。 A. NO 2 > NO 2 - >NO 2 + B. NO 2 + >NO 2 >NO 2 - C. NO 2 - > NO 2 >NO 2 + D. NO 2 + > NO 2 - >NO 2

求定积分[img=179x43]17da65388c0b1ca.png[/img]； （ ） A: log(2^(1/2) + 1)/2 + 2^(1/2)/2 B: log(2^(1/2) + 1)/2 - 2^(1/2)/2 - 1/2 C: log(2^(1/2) + 1)/2 + 2^(1/2)/2 - 1/2 D: log(2^(1/2) + 1)/2 + 2^(1/2)/2 + 1/2

2 + 2 * (2 * 2 - 2) % 2 / 3

函数z=xsiny在点(1,π/4)处的两个偏导数分别为 A: √2/2,√2/2 B: √2/2,-√2/2 C: -√2/2,-√2/2 D: -√2/2,√2/2

2×2×2×2×2

HbF的构成主要是（） A: α2β2 B: α2δ2 C: ζ2ε2 D: α2γ2 E: ζ2γ2

胎儿期血红蛋白HbF的分子组成为（ ）。 A: ζ2ε2 B: α2Aγ2、α2Gγ2 C: ζ2 Aγ2、ζ2Gγ2 D: ζ2 Aγ2、 E: α2δ2 、α2β2

正常人血红蛋白多肽链的组成是 A: α2β2 B: α2γ2 C: α2ε2 D: α2δ2 E: σ2β2

函数[img=79x27]180355ae2690a03.png[/img]在x=2处的二阶泰勒展开式为 A: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)+exp(sin(2))*(sin(2)/2-cos(2)^2/2)*(x-2)^2 B: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)-exp(sin(2))*(sin(2)/2-cos(2)^2/2)*(x-2)^2 C: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)-exp(sin(2))*(sin(2)/2+cos(2)^2/2)*(x-2)^2 D: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)+exp(sin(2))*(sin(2)/2+cos(2)^2/2)*(x-2)^2