越容易磨的煤，则其可磨系数Kkm就越小。

求由下列各曲线所围图形的面积:[tex=6.357x1.429]8/Yrok/DFaRUI5NRk863fTIeQai/YwsDNJTisno1kKM=[/tex]

已知二维随机变量 [tex=2.643x1.357]DJUMdJyw8QoCXHzomLtAYg==[/tex] 的联合密度函数为 [tex=15.929x2.429]EPaISH7F+7OFqeEao9lVbU1l5sLIxVPbOH76GHTZTAAnUXH4Qpjm2Ekoift3AQtdSzaLqP4EByLxU3lmNU3JAo+BM18UtVyaue2Eu4s/kKM=[/tex] 定义 [tex=5.929x1.357]iFsiet6JqD35SrZcdFPOeA==[/tex], 计算：(1) [tex=2.071x1.286]AABPNNktZOJp9yYomaK2LQ==[/tex] 的期望 [tex=5.214x1.357]1RnuElbUeruTNV82zX/sSA==[/tex](2) [tex=2.929x1.429]E/6h79OwUMax85KaDSxhyg==[/tex] 和 [tex=1.714x1.286]ZG2RqqBPZVx6nZ1bss/ibw==[/tex] 的期望 [tex=10.571x1.571]oibOEPzqOMutspJWiy6hNwCu/+ko3V4OQ5IcCcYbvr6NQqN/LjIS6AdjFgGINo3eVSt0CAvq1L/IP4q3E/LrBQ==[/tex](3) [tex=0.714x1.0]RRR4SYyCqv01G5bWEEMPdw==[/tex] 的期望 [tex=2.214x1.357]b1gs+TDw7pv5zQuFf6SwnQ==[/tex].

已知二维随机变量 [tex=2.643x1.357]DJUMdJyw8QoCXHzomLtAYg==[/tex] 的联合密度函数为 [tex=15.929x2.429]EPaISH7F+7OFqeEao9lVbU1l5sLIxVPbOH76GHTZTAAnUXH4Qpjm2Ekoift3AQtdSzaLqP4EByLxU3lmNU3JAo+BM18UtVyaue2Eu4s/kKM=[/tex]  定义 [tex=5.929x1.357]iFsiet6JqD35SrZcdFPOeA==[/tex], 计算:(1) [tex=2.071x1.286]AABPNNktZOJp9yYomaK2LQ==[/tex] 的方差 [tex=5.357x1.357]cElirU6wf9hOSgmBBVRmmg==[/tex](2) [tex=0.857x1.0]KGogyvwDAIJf/iL0H/9wjg==[/tex] 与 [tex=0.643x1.0]jDVSpgNhHe+VJmgvx3gg1Q==[/tex] 的协方差 [tex=4.143x1.357]i+DVPOZZfbtwzlk7qK4ILqCXBDgDfQswNtaDEEyvwG8=[/tex];(3) [tex=0.857x1.0]KGogyvwDAIJf/iL0H/9wjg==[/tex] 与 [tex=0.643x1.0]jDVSpgNhHe+VJmgvx3gg1Q==[/tex] 的相关系数 [tex=3.214x1.357]pMWXnntnWVOySRNxOPgPYw==[/tex]

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是（）。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

请仔细观察下面行列式的计算过程，如果四个等号都理解了，请选择A，否则请选择B。 | a 1 1 1 1 | |a＋4 a＋4 a＋4 a＋4 a＋4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a＋4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a＋4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a＋4)(a–1)^4

共有4个站进行码分多址通信。4个站的码片序列为：a：（-1 -1 -1 +1 +1 -1 +1 +1） b：（-1 -1 +1 -1 +1 +1 +1 -1） c：（-1 +1 -1 +1 +1 +1 -1 -1） d：（-1 +1 -1 -1 -1 -1 +1 -1） 现收到这样的码片序列：（-1 +1 -3 +1 -1 -3 +1 +1），则（ ）发送1。