• 2022-06-18 问题

    4.They asked that he was there.

    4.They asked that he was there.

  • 2021-04-14 问题

    4.They tried to reach the company for with the Burger King logo for their wedding.

    4.They tried to reach the company for with the Burger King logo for their wedding.

  • 2021-04-14 问题

    4.They had little difficulty in hooking the fish, but pulling it out of the water proved to be a big problem.( )

    4.They had little difficulty in hooking the fish, but pulling it out of the water proved to be a big problem.( )

  • 2021-04-14 问题

    4.They come at night without being called and disappear during the day without being stolen. Can you guess what are they?

    4.They come at night without being called and disappear during the day without being stolen. Can you guess what are they?

  • 2021-04-14 问题

    在所给的算式中,填上+、-、×、÷和( ),使得下面算式成立。(1)4 4 4 4=1(2)4 4 4 4=1(3)4 4 4 4=2(4)4 4 4 4=3[8分]

    在所给的算式中,填上+、-、×、÷和( ),使得下面算式成立。(1)4 4 4 4=1(2)4 4 4 4=1(3)4 4 4 4=2(4)4 4 4 4=3[8分]

  • 2021-04-14 问题

    数列-4, 4, -4, 4, -4…….

    数列-4, 4, -4, 4, -4…….

  • 2021-04-14 问题

    表达式4^4\4*4*4/4 Mod 4的值是

    表达式4^4\4*4*4/4 Mod 4的值是

  • 2021-04-14 问题

    【多选题】在下面 4 个 4 中间填上适当的运算符号和小括号使算式成立。 4 4 4 4=2 A. 4÷ 4 +4÷ 4=2 B. 4× 4÷ ( 4+ 4 ) =2 C. 4+ 4 +4 ×4=2 D. 4- ( 4 +4 ) ÷4=2 答

    【多选题】在下面 4 个 4 中间填上适当的运算符号和小括号使算式成立。 4 4 4 4=2 A. 4÷ 4 +4÷ 4=2 B. 4× 4÷ ( 4+ 4 ) =2 C. 4+ 4 +4 ×4=2 D. 4- ( 4 +4 ) ÷4=2 答

  • 2021-04-14 问题

    单音听辨。十个音为一组,含有变化音升4 [音频]/module/audioplay.html?objectid=525dda751efa2c644ef98798529599a7: *4 | 7 |升4 |-5 | 4 | 升4 |*4 | 4 |1 |*4 ||*4 | 7 |升4 |-5 | 4 | 升4 |*4 | 4 |2 |*4 ||*4 | 7 |升4 |-5 | 4 | 升4 |*4 | 6 |2 |*4 |

    单音听辨。十个音为一组,含有变化音升4 [音频]/module/audioplay.html?objectid=525dda751efa2c644ef98798529599a7: *4 | 7 |升4 |-5 | 4 | 升4 |*4 | 4 |1 |*4 ||*4 | 7 |升4 |-5 | 4 | 升4 |*4 | 4 |2 |*4 ||*4 | 7 |升4 |-5 | 4 | 升4 |*4 | 6 |2 |*4 |

  • 2022-07-29 问题

    下列哪个是《圆舞曲》的乐段结构? A: a(4)+b(4)+a(4)+c(4) B: a(4)+b(4)+a(4)a1(4) C: a(4)+b(4)+a1(4)+c(4)

    下列哪个是《圆舞曲》的乐段结构? A: a(4)+b(4)+a(4)+c(4) B: a(4)+b(4)+a(4)a1(4) C: a(4)+b(4)+a1(4)+c(4)

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