f(x)在x处可导,a,b为常数,则[img=27x32]1802fa0c04c2042.png[/img][img=234x25]1802fa0c10631ae.png[/img]= A: [img=93x26]1802fa0c195a7ad.png[/img] B: [img=93x26]1802fa0c2233a71.png[/img] C: [img=39x26]1802fa0c2adc024.png[/img] D: f(x)
f(x)在x处可导,a,b为常数,则[img=27x32]1802fa0c04c2042.png[/img][img=234x25]1802fa0c10631ae.png[/img]= A: [img=93x26]1802fa0c195a7ad.png[/img] B: [img=93x26]1802fa0c2233a71.png[/img] C: [img=39x26]1802fa0c2adc024.png[/img] D: f(x)
如果已知E(X)=3,D(X)=5,则E(X+2)[sup]2[/]=( ). A: 30 B: 26 C: 31 D: 25
如果已知E(X)=3,D(X)=5,则E(X+2)[sup]2[/]=( ). A: 30 B: 26 C: 31 D: 25
设 [img=34x25]18039e33fdb9ac5.png[/img] 在点 x 处可导,a,b为常数,则 [img=340x48]18039e340783c6d.png[/img] A: [img=39x26]18039e340fde1c1.png[/img] B: [img=93x26]18039e34182dfe3.png[/img] C: [img=93x26]18039e3420eb7aa.png[/img] D: [img=81x44]18039e3428f97ad.png[/img]
设 [img=34x25]18039e33fdb9ac5.png[/img] 在点 x 处可导,a,b为常数,则 [img=340x48]18039e340783c6d.png[/img] A: [img=39x26]18039e340fde1c1.png[/img] B: [img=93x26]18039e34182dfe3.png[/img] C: [img=93x26]18039e3420eb7aa.png[/img] D: [img=81x44]18039e3428f97ad.png[/img]
lim[√(x²+x)-√(x²-x)],x→∞
lim[√(x²+x)-√(x²-x)],x→∞
设f(x)=3x,g(x)=x2,则函数g[f(x)]-f[g(x)]=()。
设f(x)=3x,g(x)=x2,则函数g[f(x)]-f[g(x)]=()。
[lncos(x-1)]/[1-sin(πx/2)]x≠1
[lncos(x-1)]/[1-sin(πx/2)]x≠1
怎么证明D(X)=E(X^2)-[E(X)]^2和D(X)=E[X-E(X)]^2
怎么证明D(X)=E(X^2)-[E(X)]^2和D(X)=E[X-E(X)]^2
计算x÷6/35=26/45×13/25
计算x÷6/35=26/45×13/25
设f(x)=1/1-x求f[f(x)]和f{f[f(x)]}
设f(x)=1/1-x求f[f(x)]和f{f[f(x)]}
已知列表lst=[ [‘苹果’,’红色’] , [‘葡萄’,’紫色’] , [‘草莓’,’红色’] ],则以下能够获取所有水果名称列表的表达式是: A: [ x[0] for x in lst ] B: [ x[1] for x in lst ] C: [ x(0) for x in lst ] D: [ x for x in lst if x==’水果’]
已知列表lst=[ [‘苹果’,’红色’] , [‘葡萄’,’紫色’] , [‘草莓’,’红色’] ],则以下能够获取所有水果名称列表的表达式是: A: [ x[0] for x in lst ] B: [ x[1] for x in lst ] C: [ x(0) for x in lst ] D: [ x for x in lst if x==’水果’]