• 2022-06-12 问题

    已知函数f(x)是定义在实数集R上的奇函数,且f(x)在[3,5]上是增函数,若f(5)=-2,则f(-5)、f(-3)、f(0)的大小关系是( ). A: f(0)<(-5)<f(-3) B: f(-5)<f(-3)<f(0) C: f(-3)<f(-5)<f(0) D: f(0)<f(-3)<f(-5)

    已知函数f(x)是定义在实数集R上的奇函数,且f(x)在[3,5]上是增函数,若f(5)=-2,则f(-5)、f(-3)、f(0)的大小关系是( ). A: f(0)<(-5)<f(-3) B: f(-5)<f(-3)<f(0) C: f(-3)<f(-5)<f(0) D: f(0)<f(-3)<f(-5)

  • 2021-04-14 问题

    f(x)在[0,1]上有连续的二阶导数,f(0)=f(1)=0,任意x属于[0,...715af2ac3f81f8.png"]

    f(x)在[0,1]上有连续的二阶导数,f(0)=f(1)=0,任意x属于[0,...715af2ac3f81f8.png"]

  • 2022-10-26 问题

    设函数y=f(x)有二阶导数,对任意实数x,满足:f(x)=-f(-x)及f(x)=f(x+1),若f'(1)>0,则有 ( ) A: f"(-5)≤f'(-5)≤f(-5) B: f(-5)=f"(-5)<f'(-5) C: f'(-5)≤f(-5)≤f"(-5) D: f(-5)<f(-5)=f"(-5)

    设函数y=f(x)有二阶导数,对任意实数x,满足:f(x)=-f(-x)及f(x)=f(x+1),若f'(1)>0,则有 ( ) A: f"(-5)≤f'(-5)≤f(-5) B: f(-5)=f"(-5)<f'(-5) C: f'(-5)≤f(-5)≤f"(-5) D: f(-5)<f(-5)=f"(-5)

  • 2021-04-14 问题

    函数f(x)=x²-5x+8,则f’(x)=3x²-5,f’(0)=-5

    函数f(x)=x²-5x+8,则f’(x)=3x²-5,f’(0)=-5

  • 2021-04-14 问题

    函数f(x)=x²-5x+8,则f’(x)=3x²-5,f’(0)=-5(1.0分)

    函数f(x)=x²-5x+8,则f’(x)=3x²-5,f’(0)=-5(1.0分)

  • 2022-05-31 问题

    fx=1/2^x+根号2,求f(-5)+f(-4)+...+f(0)

    fx=1/2^x+根号2,求f(-5)+f(-4)+...+f(0)

  • 2022-06-19 问题

    若函数f(x)=kx+3满足条件f(1)=0,则f(5)=______。

    若函数f(x)=kx+3满足条件f(1)=0,则f(5)=______。

  • 2022-11-01 问题

    已知函数f(X)是奇函数,f(3)=5,则f(-3)= ( A: -5 B: 0 C: 5 D: 无法确定

    已知函数f(X)是奇函数,f(3)=5,则f(-3)= ( A: -5 B: 0 C: 5 D: 无法确定

  • 2021-04-14 问题

    【单选题】a设 f ( x ) 在 [ 0 , 1 ] 满足 f ′′ ( x ) > 0 ,则下列不等式中正确的是() A. f ′ ( 1 ) > f ′ ( 0 ) > f ( 1 ) − f ( 0 ) " role="presentation"> f ′ ( 1 ) > f ′ ( 0 ) > f ( 1 ) − f ( 0 ) B. f ′ ( 1 ) > f ( 1 ) − f ( 0 ) > f ′ ( 0 ) " role="presentation"> f ′ ( 1 ) > f ( 1 ) − f ( 0 ) > f ′ ( 0 ) C. f ( 1 ) − f ( 0 ) > f ′ ( 1 ) > f ′ ( 0 ) " role="presentation"> f ( 1 ) − f ( 0 ) > f ′ ( 1 ) > f ′ ( 0 ) D. f ′ ( 1 ) > f ( 0 ) − f ( 1 ) > f ′ ( 0 ) " role="presentation"> f ′ ( 1 ) > f ( 0 ) − f ( 1 ) > f ′ ( 0 )

    【单选题】a设 f ( x ) 在 [ 0 , 1 ] 满足 f ′′ ( x ) > 0 ,则下列不等式中正确的是() A. f ′ ( 1 ) > f ′ ( 0 ) > f ( 1 ) − f ( 0 ) " role="presentation"> f ′ ( 1 ) > f ′ ( 0 ) > f ( 1 ) − f ( 0 ) B. f ′ ( 1 ) > f ( 1 ) − f ( 0 ) > f ′ ( 0 ) " role="presentation"> f ′ ( 1 ) > f ( 1 ) − f ( 0 ) > f ′ ( 0 ) C. f ( 1 ) − f ( 0 ) > f ′ ( 1 ) > f ′ ( 0 ) " role="presentation"> f ( 1 ) − f ( 0 ) > f ′ ( 1 ) > f ′ ( 0 ) D. f ′ ( 1 ) > f ( 0 ) − f ( 1 ) > f ′ ( 0 ) " role="presentation"> f ′ ( 1 ) > f ( 0 ) − f ( 1 ) > f ′ ( 0 )

  • 2022-06-19 问题

    设f(x)在[0,π]上二阶连续可导,且f(π)=2满足∫π0(f(x)+f″(x))sinxdx=5,试计算f(0)的值.

    设f(x)在[0,π]上二阶连续可导,且f(π)=2满足∫π0(f(x)+f″(x))sinxdx=5,试计算f(0)的值.

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