从某细菌中分离的DNA样品内含有15.1%的腺嘌呤,那么其它碱基的百分含量是:() A: G=34.9% B: C=15.1% C: T=34.9% D: G=69.8% E: C=30.2%
从某细菌中分离的DNA样品内含有15.1%的腺嘌呤,那么其它碱基的百分含量是:() A: G=34.9% B: C=15.1% C: T=34.9% D: G=69.8% E: C=30.2%
2019年上半年,第三产业占GDP比重为( ) A: 34.9% B: 44.9% C: 54.9% D: 64.9%
2019年上半年,第三产业占GDP比重为( ) A: 34.9% B: 44.9% C: 54.9% D: 64.9%
已知单位反馈系统的开环传递函数为[img=222x48]1802d8db2b220cd.png[/img],设计校正网络,使[img=279x25]1802d8db35e72a6.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]1802d8db2b220cd.png[/img],设计校正网络,使[img=279x25]1802d8db35e72a6.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]1802d8b4ff8a2f4.png[/img],设计校正网络,使[img=279x25]1802d8b50a755d0.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]1802d8b4ff8a2f4.png[/img],设计校正网络,使[img=279x25]1802d8b50a755d0.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]180339e21c47fc8.png[/img],设计校正网络,使[img=279x25]180339e2273bb1e.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]180339e21c47fc8.png[/img],设计校正网络,使[img=279x25]180339e2273bb1e.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]1803876ff8871a0.png[/img],设计校正网络,使[img=279x25]1803877003e7b9a.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]1803876ff8871a0.png[/img],设计校正网络,使[img=279x25]1803877003e7b9a.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]18032bc15a38428.png[/img],设计校正网络,使[img=279x25]18032bc16519c2b.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]18032bc15a38428.png[/img],设计校正网络,使[img=279x25]18032bc16519c2b.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]1803795a19a3062.png[/img],设计校正网络,使[img=279x25]1803795a24730a1.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]1803795a19a3062.png[/img],设计校正网络,使[img=279x25]1803795a24730a1.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]18036007bd5aead.png[/img],设计校正网络,使[img=279x25]18036007c8703d3.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]18036007bd5aead.png[/img],设计校正网络,使[img=279x25]18036007c8703d3.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]18038f4c3cdf3d9.png[/img],设计校正网络,使[img=279x25]18038f4c474ee02.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8
已知单位反馈系统的开环传递函数为[img=222x48]18038f4c3cdf3d9.png[/img],设计校正网络,使[img=279x25]18038f4c474ee02.png[/img]。则串入滞后校正网络的参数为( ) A: b = 0.112, T = 34.9 B: b = 0.106, T = 34.9 C: b = 0.112, T = 57.8 D: b = 0.106, T = 57.8