6.I'll go with you as soon as I ____ my work. A: will finish B: shall finish C: finish D: finished
6.I'll go with you as soon as I ____ my work. A: will finish B: shall finish C: finish D: finished
6.I am tired and I don't feel like _____ any further. A: to walk B: to be walking C: walking D: walk
6.I am tired and I don't feel like _____ any further. A: to walk B: to be walking C: walking D: walk
6.I will turn her room into a ( )room.
6.I will turn her room into a ( )room.
6.I’m _______<br/>to getting fit this year, so I’ve taken up cycling.( ) A: motivation B: committed C: accessible D: conversational
6.I’m _______<br/>to getting fit this year, so I’ve taken up cycling.( ) A: motivation B: committed C: accessible D: conversational
执行循环后,()中i的值是6。 A: for(i=1;i<=6;i++){ } B: for(i=1;i<6;i++){ } C: for(i=0;i<=6;i=i+2){ } D: for(i=10;i>=6;i--){ }
执行循环后,()中i的值是6。 A: for(i=1;i<=6;i++){ } B: for(i=1;i<6;i++){ } C: for(i=0;i<=6;i=i+2){ } D: for(i=10;i>=6;i--){ }
对下面程序段的运行结果是( )。 int a[6][6],i,j; for(i=1;i<6;i++) for(j=1;j<6;j++) a[i][j]=(i/j) * (j/i); for(i=1;i<6;i++) { for(j=1;j<6;j++) printf("%2d",a[i][j]); printf("\n"); }
对下面程序段的运行结果是( )。 int a[6][6],i,j; for(i=1;i<6;i++) for(j=1;j<6;j++) a[i][j]=(i/j) * (j/i); for(i=1;i<6;i++) { for(j=1;j<6;j++) printf("%2d",a[i][j]); printf("\n"); }
Dimension a(6) a(1)=1 a(2)=1 FOR i=3 TO 6 a(i)=a(i-1)+a(i-2) NEXT ?a(6)
Dimension a(6) a(1)=1 a(2)=1 FOR i=3 TO 6 a(i)=a(i-1)+a(i-2) NEXT ?a(6)
运行以下代码,i的值应该是: int i=6; do { i=i+5; if(i%3==0) i=i+5; else i=i-12; }while(i>;=-6); printf("i=%d\n",i); A: -6 B: -7 C: -9 D: -8
运行以下代码,i的值应该是: int i=6; do { i=i+5; if(i%3==0) i=i+5; else i=i-12; }while(i>;=-6); printf("i=%d\n",i); A: -6 B: -7 C: -9 D: -8
运行以下程序输出的结果是:( )。i=10while i>;=6:i=i-1if i%4==0:continueelse:print(i,end=' ') A: 10 9 8 7 6 B: 9 8 7 6 5 C: 10 9 7 6 D: 9 7 6 5
运行以下程序输出的结果是:( )。i=10while i>;=6:i=i-1if i%4==0:continueelse:print(i,end=' ') A: 10 9 8 7 6 B: 9 8 7 6 5 C: 10 9 7 6 D: 9 7 6 5
下面程序的运行结果是( ) int main() { int a[6],i; for(i=1;i<6;i++) { a[i]=9*(i-2+4*(i>3))%5; printf("%2d",a[i]); } }
下面程序的运行结果是( ) int main() { int a[6],i; for(i=1;i<6;i++) { a[i]=9*(i-2+4*(i>3))%5; printf("%2d",a[i]); } }