考虑下面的属性文法G(S)：产 生 式语 义 规 则S ® ABCprint A.num, B.num, C.num A ® [img=20x22]1803d73211b24cd.png[/img] aA.num = [img=20x22]1803d73211b24cd.png[/img].num + 1A ® εA.num = 0B ®[img=20x22]1803d7322247642.png[/img]bB.num = [img=20x22]1803d7322247642.png[/img].num + 1B ® εB.num = 0C ®[img=20x22]1803d7323424a77.png[/img] cC.num = [img=20x22]1803d7323424a77.png[/img].num + 1C ® εC.num = 0对于输入字符串aabbbc进行语法分析和属性计算，输出结果是 A: 1 2 3 B: 3 2 1 C: 2 3 1 D: 2 1 3

考虑下面的属性文法G(S)：产 生 式语 义 规 则S ® ABC print A.num, B.num, C.num A ® [img=20x22]18035825cebcda4.png[/img] aA.num = [img=20x22]18035825cebcda4.png[/img].num + 1A ® εA.num = 0B ® [img=20x22]18035825e1973dc.png[/img] bB.num = [img=20x22]18035825e1973dc.png[/img].num + 1B ® εB.num = 0C ® [img=20x22]18035825f2dc704.png[/img] cC.num = [img=20x22]18035825f2dc704.png[/img].num + 1C ® εC.num = 0对于输入字符串aabbbc进行语法分析和属性计算，输出结果是 A: 1 2 3 B: 3 2 1 C: 2 3 1 D: 2 1 3

考虑下面的属性文法G(S)：产 生 式语 义 规 则S ® ABC print A.num, B.num, C.num A ® [img=20x22]1803d731db39d57.png[/img] aA.num = [img=20x22]1803d731db39d57.png[/img].num + 1A ® εA.num = 0B ® [img=20x22]1803d731ec91e62.png[/img] bB.num = [img=20x22]1803d731ec91e62.png[/img].num + 1B ® εB.num = 0C ® [img=20x22]1803d731fcad3f0.png[/img] cC.num = [img=20x22]1803d731fcad3f0.png[/img].num + 1C ® εC.num = 0对于输入字符串aabbbc进行语法分析和属性计算，输出结果是 A: 1 2 3 B: 3 2 1 C: 2 3 1 D: 2 1 3

unsignedcharnum;num=0X98;num=num%10;num=num%10;num=?() A: 15 B: 8 C: 9 D: 2

关于属性的使用正确的是 A: private int num;public string Num{get{return num;} set{num=value;}} B: private int num;public int Num{get{return num;}set{num=value;}} C: private int num;public int Num{get{num=value;}set{return num;}} D: private int num;private int Num{get{return num;}set{num=value;}}

@num = (3,5,2,1,4);@num = sort(@num);push(@num, (6,7,8,9));pop(@num);shift(@num);执行以上语句后，@num=？ A: (2,3,4,5,6,7,8) B: (3,5,2,1,4,6,7,8,9) C: (1,2,3,4,5,6,7,8,9) D: (1,2,3,4,5,6,7,8)

3、描述“变量num取值范围为10--100或为负数”的逻辑表达式为（）。 A: ( num>;10 || num<;100 ) &amp;&amp; (num<;0 ) B: ( num>;10 || num<;100 ) || (num<;0 ) C: ( num>;10 &amp;&amp; num<;100 ) &amp;&amp; (num<;0 ) D: ( num>;10 &amp;&amp; num<;100 ) || (num<;0 )

有如下程序，输入一个int型的整数num，逆向输出其各位数字，同时求出其各位以及各位数字之和。 #include#includevoid main() { int num,sum=0,k,i=0; cin>;>;num; while(num>;0) { (1) ; cout<; A: k=num%10 num=num/10 B: num=num%10 k=num/10 C: num=num/10 k=num%10 D: k=num/10 num=num%10

关于属性的使用正确的是? private int num;public string Num{get{return num;};set{num=value;}}|private int num;private int Num{get{return num;}set{num=value;}}|private int num;public int Num{get{return num;}set{num=value;}}|private int num;public int Num{get{num=value;}set{return num;}}

中国大学MOOC: @num = (3,5,2,1,4);@num = sort(@num);push(@num, (6,7,8,9));pop(@num);shift(@num);执行以上语句后，@num=？