• 2022-05-29 问题

    求不定积分∫(5^x+x^5)dx

    求不定积分∫(5^x+x^5)dx

  • 2022-06-04 问题

    设(DX)=10111011B,(CL)=3,(CF)=1,求下列指令单独执行后DX的内容:答案写成4位16进制数形式。 (1)SHR DX,1; DX = (2)SAR DX,CL; DX = (3)SHL DX,CL; DX = (4)ROR DX,CL; DX = (5)RCL DX,CL; DX =

    设(DX)=10111011B,(CL)=3,(CF)=1,求下列指令单独执行后DX的内容:答案写成4位16进制数形式。 (1)SHR DX,1; DX = (2)SAR DX,CL; DX = (3)SHL DX,CL; DX = (4)ROR DX,CL; DX = (5)RCL DX,CL; DX =

  • 2022-06-04 问题

    设DX=78C5H,CL=5,CF=1,确定下列各条指令执行后DX和CF中的值。(1)SHR DX, 1 (2)SAR DX, CL(3)ROR DX, CL

    设DX=78C5H,CL=5,CF=1,确定下列各条指令执行后DX和CF中的值。(1)SHR DX, 1 (2)SAR DX, CL(3)ROR DX, CL

  • 2022-05-31 问题

    求积分∫ln(x^2/5)dx

    求积分∫ln(x^2/5)dx

  • 2022-06-06 问题

    1.∫(sinx)^5(cosx)^3dx2.∫(sinx)²(cosx)²dx

    1.∫(sinx)^5(cosx)^3dx2.∫(sinx)²(cosx)²dx

  • 2022-07-23 问题

    如下命令中不能实现如下微分方程组[img=327x203]17e443a5d83ce02.png[/img],在初值条件[img=172x112]17e443a5e2ead01.png[/img]下的特解求解的是: A: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1', 'y(0)=0', 't') B: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1, y(0)=0', 't') C: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1', 'y(0)=0') D: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1', 'y(0)=0', 'x')

    如下命令中不能实现如下微分方程组[img=327x203]17e443a5d83ce02.png[/img],在初值条件[img=172x112]17e443a5e2ead01.png[/img]下的特解求解的是: A: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1', 'y(0)=0', 't') B: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1, y(0)=0', 't') C: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1', 'y(0)=0') D: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1', 'y(0)=0', 'x')

  • 2022-06-16 问题

    不计算积分比较∫【0到1】(x^2)dx与∫【0到1】(x^5)dx积分值的大小

    不计算积分比较∫【0到1】(x^2)dx与∫【0到1】(x^5)dx积分值的大小

  • 2022-06-19 问题

    计算∫20(x2+1)dx=(  ) A: 143 B: 5 C: 113 D: 83

    计算∫20(x2+1)dx=(  ) A: 143 B: 5 C: 113 D: 83

  • 2022-06-17 问题

    设DX=4, DY=5, D(X-Y)=8,则Cov(X,Y)=________.

    设DX=4, DY=5, D(X-Y)=8,则Cov(X,Y)=________.

  • 2022-05-26 问题

    计算下列积分∫上限是5下限是0((2x^2+3x-5)dx/(x+3))

    计算下列积分∫上限是5下限是0((2x^2+3x-5)dx/(x+3))

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