以下程序的执行结果是 #include < lostream >#include < stack >using nanespace std;void main( ){ stack< int> s; s. push(1); s. push(2); s. push(3); s. push(4); cout << "s.size:" < s.size() << ",s:"; while (!s. eapty()) { cout<s.top()<”; s. pop(); cout < endl;} A: s. size; 3, s: 123 B: s. size: 3, s: 432 C: s. size: 4, s; 1234 D: s. size: 4, s: 4321
以下程序的执行结果是 #include < lostream >#include < stack >using nanespace std;void main( ){ stack< int> s; s. push(1); s. push(2); s. push(3); s. push(4); cout << "s.size:" < s.size() << ",s:"; while (!s. eapty()) { cout<s.top()<”; s. pop(); cout < endl;} A: s. size; 3, s: 123 B: s. size: 3, s: 432 C: s. size: 4, s; 1234 D: s. size: 4, s: 4321
What day was it yesterday A: It’s Sam’s. B: It’s Mike’s. C: It’s mine.
What day was it yesterday A: It’s Sam’s. B: It’s Mike’s. C: It’s mine.
What were the millionaires average scores in college A: A’s and B’s. B: B’s and C’s. C: C’s and D’s. D: Not mentioned.
What were the millionaires average scores in college A: A’s and B’s. B: B’s and C’s. C: C’s and D’s. D: Not mentioned.
E-commerce, which has long been ()stronghold. A: Facebook’s. B: Google’s . C: Apple’s. D: Amazon’s.
E-commerce, which has long been ()stronghold. A: Facebook’s. B: Google’s . C: Apple’s. D: Amazon’s.
There is ______ ID in the bag. It’s ______ Jill’s.
There is ______ ID in the bag. It’s ______ Jill’s.
Henry’s baggage is ______ as Rachel’s.
Henry’s baggage is ______ as Rachel’s.
Mrs.White's birthday ______ her husband's.
Mrs.White's birthday ______ her husband's.
Stephen’s house is so large as John's.
Stephen’s house is so large as John's.
T. S. Eliot’s poem, ________, ...modern civilization.
T. S. Eliot’s poem, ________, ...modern civilization.
实现“查询学生及其选课情况(基于左外连接)”的SELECT语句为()。A.SELECT S.*, C.* FROM Student S JOIN SC ON S.Sno=SC.SnoB.SELECT S.*, C.* FROM Student S LEFT JOIN SC ON S.Sno=SC.SnoC.SELECT S.*, C.* FROM Student S, SC WHERE S.Sno=SC.SnoD.SELECT S.*, C.* FROM Student S OUTER JOIN SC ON S.Sno=SC.Sno
实现“查询学生及其选课情况(基于左外连接)”的SELECT语句为()。A.SELECT S.*, C.* FROM Student S JOIN SC ON S.Sno=SC.SnoB.SELECT S.*, C.* FROM Student S LEFT JOIN SC ON S.Sno=SC.SnoC.SELECT S.*, C.* FROM Student S, SC WHERE S.Sno=SC.SnoD.SELECT S.*, C.* FROM Student S OUTER JOIN SC ON S.Sno=SC.Sno