下列程序段的执行结果是Dima(5)AsStringDimbAsIntegerDimIAsIntegerForI=0To5a(I)=I+1Debug.Printa(I)NextI A: 123456 B: 6 C: 654321 D: 0
下列程序段的执行结果是Dima(5)AsStringDimbAsIntegerDimIAsIntegerForI=0To5a(I)=I+1Debug.Printa(I)NextI A: 123456 B: 6 C: 654321 D: 0
1