有表song(id,song_name,album,play_count,fav_count)分别表示歌曲的主键id、歌曲名、专辑名、播放次数和收藏次数，以下与order by相关的sql错误的是： A: select * from song order by play_count asc; B: select * from song order by (play_count + fav_count) asc; C: select * from song order by fav_count desc where play_count > 5; D: select * from song order by id,play_count asc,fav_count desc;

count = 0while count < 5： print（ count） count = count + 2print( “Over!")

I’d rather ______ the piano than ______ the violin. A: play; playing B: to play; playing C: play; play D: to play; play

【单选题】You’d better on work time, or the boss may be angry with you. not play not to play to not play A. not play B. not to play C. to not play

阅读以下程序public class Count{static int count;int number;public Count(){count = count + 1;number = count;}}class Test{public static void Main(){Count a = new Count();Count b = new Count();Count c = new Count();}}程序运行后，对象a的count值是（） A: 0 B: 1 C: 2 D: 3

count = 0 while count < 5: print (count, " 小于 5") count = count + 1 else: print (count, " 大于或等于 5")

下列if语句中，程序风格最规范的是（）。 A: if (count >;= 100) count = 0; B: if (count >;= 100) {count = 0;} C: if (count >;= 100)count = 0; D: if (count >;= 100){count = 0;}

‎下面（）是函数重载。‏ A: void play(int) 和void play(float) B: play( ) 和 ~play() C: void play(int) 和int play(int) D: void play( ) 和int play( )

下面（　　）是函数重载。 A: void play(int) 和void play(float) B: play( ) 和 ~play() C: void play(int) 和int play(int) D: void play( ) 和int play( )

有表song(id,song_name,album,play_count,fav_count)分别表示歌曲的主键id、歌曲名、专辑名、播放次数和收藏次数。要求查询超过两首歌的专辑与其歌曲数，并且按专辑名排序；有同学给出如下sql语句： select id,count(*) from song order by albumgroup[br][/br]by album having count(*)>2 ; 这个sql错误的地方是： A: order by 后面跟group by语句 B: album没有出现在select语句中 C: 在having条件中使用了count(*) D: 这个sql语句没有错误