• 2022-06-05 问题

    中国大学MOOC: Words and StructuresTask 1 Complete each statement by choosing the appropriate answer from the four choices marked A, B, C and D.1. Many of your suggestions have been in the plan.

    中国大学MOOC: Words and StructuresTask 1 Complete each statement by choosing the appropriate answer from the four choices marked A, B, C and D.1. Many of your suggestions have been in the plan.

  • 2022-06-09 问题

    There are 10 incomplete sentences. Complete each one by deciding on the most appropriate word or expression from the four choices marked A, B, C and D.1. The ___________ of a big new machine can be hard to learn. A: operate B: operation C: operating D: operative

    There are 10 incomplete sentences. Complete each one by deciding on the most appropriate word or expression from the four choices marked A, B, C and D.1. The ___________ of a big new machine can be hard to learn. A: operate B: operation C: operating D: operative

  • 2022-06-09 问题

    共有4个站进行码分多址通信。4个站的码片序列为:a:(-1 -1 -1 +1 +1 -1 +1 +1) b:(-1 -1 +1 -1 +1 +1 +1 -1)c:(-1 +1 -1 +1 +1 +1 -1 -1) d:(-1 +1 -1 -1 -1 -1 +1 -1)现收到这样的码片序列:(+1 +1 -1 +3 +1 +1 -3 +1),则( )发送1。 A: a和d B: a C: b和c D: c

    共有4个站进行码分多址通信。4个站的码片序列为:a:(-1 -1 -1 +1 +1 -1 +1 +1) b:(-1 -1 +1 -1 +1 +1 +1 -1)c:(-1 +1 -1 +1 +1 +1 -1 -1) d:(-1 +1 -1 -1 -1 -1 +1 -1)现收到这样的码片序列:(+1 +1 -1 +3 +1 +1 -3 +1),则( )发送1。 A: a和d B: a C: b和c D: c

  • 2022-10-25 问题

    下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

    下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

  • 2022-06-19 问题

    点( 1,1, 1)对于z轴的对称点为( ) A: ( -1, -1, 1) B: ( 1, -1, -1) C: ( -1, 1, -1) D: ( -1, -1, -1)

    点( 1,1, 1)对于z轴的对称点为( ) A: ( -1, -1, 1) B: ( 1, -1, -1) C: ( -1, 1, -1) D: ( -1, -1, -1)

  • 2022-06-14 问题

    设集合A={1,a},则P(A)=() A: {{1},{a}} B: {,{1},{a}} C: {,{1},{a},{1,a}} D: {{1},{a},{1,a}}

    设集合A={1,a},则P(A)=() A: {{1},{a}} B: {,{1},{a}} C: {,{1},{a},{1,a}} D: {{1},{a},{1,a}}

  • 2021-04-14 问题

    共有 4 个站进行码分多址通信。 4 个站的码片序列为: a :( -1 -1 -1 1 1 -1 1 1 ) b :( -1 -1 1 -1 1 1 1 -1 ) c :( -1 1 -1 1 1 1 -1 -1 ) d :( -1 1 -1 -1 -

    共有 4 个站进行码分多址通信。 4 个站的码片序列为: a :( -1 -1 -1 1 1 -1 1 1 ) b :( -1 -1 1 -1 1 1 1 -1 ) c :( -1 1 -1 1 1 1 -1 -1 ) d :( -1 1 -1 -1 -

  • 2022-07-29 问题

    ‏语句[X,D]=eig(A)执行后,A*X(:,1)和D(1)*X(:,1)的关系是()。‌ A: A*X(:,1)大于D(1)*X(:,1) B: A*X(:,1)小于D(1)*X(:,1) C: 在数学意义上A*X(:,1)等于D(1)*X(:,1) D: 两者关系不确定

    ‏语句[X,D]=eig(A)执行后,A*X(:,1)和D(1)*X(:,1)的关系是()。‌ A: A*X(:,1)大于D(1)*X(:,1) B: A*X(:,1)小于D(1)*X(:,1) C: 在数学意义上A*X(:,1)等于D(1)*X(:,1) D: 两者关系不确定

  • 2022-06-11 问题

    把十进制数55转换成二进制数为( )。 A: 1 1 0 1 1 0 B: 1 1 0 1 1 1 C: 1 1 0 1 0 1 D: 1 0 1 1 1

    把十进制数55转换成二进制数为( )。 A: 1 1 0 1 1 0 B: 1 1 0 1 1 1 C: 1 1 0 1 0 1 D: 1 0 1 1 1

  • 2022-07-24 问题

    下列哪一种方法可以得到RDD(('a',1))()。 A: RDD(('a',1),('b',1)) union RDD(('a',1),('b',1)) B: RDD(('a',1),('b',1)) join RDD(('a',1),('b',1)) C: RDD(('a',1),('b',1)) intersection RDD(('a',1),('d',1)) D: RDD(('a',1),('b',1)) subtract RDD(('a',1),('b',1))

    下列哪一种方法可以得到RDD(('a',1))()。 A: RDD(('a',1),('b',1)) union RDD(('a',1),('b',1)) B: RDD(('a',1),('b',1)) join RDD(('a',1),('b',1)) C: RDD(('a',1),('b',1)) intersection RDD(('a',1),('d',1)) D: RDD(('a',1),('b',1)) subtract RDD(('a',1),('b',1))

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