• 2022-05-26 问题

    用R程序编程求下列的值,正确的命令是 ( )[img=76x44]180398c776266cb.jpg[/img] A: (sin(50*180/pi))^2/(1+ sin(10*180/pi)) B: (sin(50*π/180))^2/(1+ sin(10*π/180)) C: sin(50)^2/(1+ sin(10)) D: (sin(50*pi/180))^2/(1+ sin(10*pi/180))

    用R程序编程求下列的值,正确的命令是 ( )[img=76x44]180398c776266cb.jpg[/img] A: (sin(50*180/pi))^2/(1+ sin(10*180/pi)) B: (sin(50*π/180))^2/(1+ sin(10*π/180)) C: sin(50)^2/(1+ sin(10)) D: (sin(50*pi/180))^2/(1+ sin(10*pi/180))

  • 2022-06-30 问题

    函数[img=79x27]180355ae2690a03.png[/img]在x=2处的二阶泰勒展开式为 A: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)+exp(sin(2))*(sin(2)/2-cos(2)^2/2)*(x-2)^2 B: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)-exp(sin(2))*(sin(2)/2-cos(2)^2/2)*(x-2)^2 C: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)-exp(sin(2))*(sin(2)/2+cos(2)^2/2)*(x-2)^2 D: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)+exp(sin(2))*(sin(2)/2+cos(2)^2/2)*(x-2)^2

    函数[img=79x27]180355ae2690a03.png[/img]在x=2处的二阶泰勒展开式为 A: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)+exp(sin(2))*(sin(2)/2-cos(2)^2/2)*(x-2)^2 B: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)-exp(sin(2))*(sin(2)/2-cos(2)^2/2)*(x-2)^2 C: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)-exp(sin(2))*(sin(2)/2+cos(2)^2/2)*(x-2)^2 D: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)+exp(sin(2))*(sin(2)/2+cos(2)^2/2)*(x-2)^2

  • 2022-06-17 问题

    sin(α-β)cosβ+cos(α-β)sinβ=( ) A: sin(α-2β) B: cos(α-2β) C: sinα D: cosα

    sin(α-β)cosβ+cos(α-β)sinβ=( ) A: sin(α-2β) B: cos(α-2β) C: sinα D: cosα

  • 2022-06-05 问题

    将正弦电压u= 10 sin( 314t+30°) V 施加于感抗XL = 5 W的电感元件上,则通过该元件的电流i = ( )。[img=114x55]1802f8dcf43e45a.jpg[/img] A: 50 sin( 314t+90°) A B: 2 sin( 314t+60°) A C: 2 sin( 314t-60°) A D: 5 sin( 314t-60°) A

    将正弦电压u= 10 sin( 314t+30°) V 施加于感抗XL = 5 W的电感元件上,则通过该元件的电流i = ( )。[img=114x55]1802f8dcf43e45a.jpg[/img] A: 50 sin( 314t+90°) A B: 2 sin( 314t+60°) A C: 2 sin( 314t-60°) A D: 5 sin( 314t-60°) A

  • 2022-06-11 问题

    将正弦电压u = 10 sin( 314 t +30 ) V 施加于感抗XL = 5 的电感元件上,<br/>则通过该元件的电流 i = ( ) 。 A: 50 sin( 314 t +90 ) B: 2 sin( 314 t +60 ) C: 2 sin( 314 t -60 ) D: 2 sin( 314 t -30 )

    将正弦电压u = 10 sin( 314 t +30 ) V 施加于感抗XL = 5 的电感元件上,<br/>则通过该元件的电流 i = ( ) 。 A: 50 sin( 314 t +90 ) B: 2 sin( 314 t +60 ) C: 2 sin( 314 t -60 ) D: 2 sin( 314 t -30 )

  • 2022-07-28 问题

    以下不能正确计算代数式值的C语言表达式是() A: 1/3*sin(1/2)*sin(1/2) B: sin(0.5)*sin(0.5)/3 C: pow(sin(0.5),2)/3 D: 1/3.0*pow(sin(1.0/2),2)

    以下不能正确计算代数式值的C语言表达式是() A: 1/3*sin(1/2)*sin(1/2) B: sin(0.5)*sin(0.5)/3 C: pow(sin(0.5),2)/3 D: 1/3.0*pow(sin(1.0/2),2)

  • 2022-05-31 问题

    曲线积分$$\int_{(0,0}^{(x,y)}(2x\cos y-y^2\sin x)dx+(2y\cos x-x^2\sin y)dy=$$ A: $y^2\cos x+x^2\cos y$ B: $x^2\cos x+y^2\cos y$ C: $x^2\sin y+y^2\sin x$ D: $x^2\sin x+y^2\sin y$

    曲线积分$$\int_{(0,0}^{(x,y)}(2x\cos y-y^2\sin x)dx+(2y\cos x-x^2\sin y)dy=$$ A: $y^2\cos x+x^2\cos y$ B: $x^2\cos x+y^2\cos y$ C: $x^2\sin y+y^2\sin x$ D: $x^2\sin x+y^2\sin y$

  • 2022-06-17 问题

    已知sin(α+β)=2/1,sin(α-β)=3/1求证:sinαcosβ=5cosαsinβ

    已知sin(α+β)=2/1,sin(α-β)=3/1求证:sinαcosβ=5cosαsinβ

  • 2022-05-27 问题

    $\int {{{\sin 2x} \over {1 + {{\sin }^4}x}}} {\rm{d}}x = $ A: $\arctan (\sin x) + C$ B: $\arctan ({\sin ^2}x) + C$ C: ${\arctan ^2}(\sin x) + C$ D: $ - {\arctan ^2}(\sin x) + C$

    $\int {{{\sin 2x} \over {1 + {{\sin }^4}x}}} {\rm{d}}x = $ A: $\arctan (\sin x) + C$ B: $\arctan ({\sin ^2}x) + C$ C: ${\arctan ^2}(\sin x) + C$ D: $ - {\arctan ^2}(\sin x) + C$

  • 2022-06-05 问题

    将正弦电压u =10 sin ( 314t + 30°) V 施加于电阻为5 W的电阻元件上,则通过该元件的电流i =( )。[img=146x69]17d6049d72f166b.png[/img] A: 2 sin314t A B: 2 sin( 314t-30°) A C: 2 sin( 314t+30°) A

    将正弦电压u =10 sin ( 314t + 30°) V 施加于电阻为5 W的电阻元件上,则通过该元件的电流i =( )。[img=146x69]17d6049d72f166b.png[/img] A: 2 sin314t A B: 2 sin( 314t-30°) A C: 2 sin( 314t+30°) A

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