• 2021-04-14 问题

    有如下函数过程: Function secproc(x As Integer, y As Integer, z As Integer) secproc = 3 * y + z + 2 * x End Function Private Sub Command1_Click() Dim a As Integer, b As Integer, c As Integer a = 2: b = 3: c = 4 Print secproc(c, b, a) End Sub 该程序的运行结果是( )。

    有如下函数过程: Function secproc(x As Integer, y As Integer, z As Integer) secproc = 3 * y + z + 2 * x End Function Private Sub Command1_Click() Dim a As Integer, b As Integer, c As Integer a = 2: b = 3: c = 4 Print secproc(c, b, a) End Sub 该程序的运行结果是( )。

  • 2021-04-14 问题

    有如下函数过程:Functionsecproc(xAsInteger,yAsInteger,zAsInteger)secproc=3*yz2*xEndFunctionPrivateSubCommand1_Click()DimaAsInteger,bAsInteger,cAsIntegera=2:b=3:c=4Printsecproc(c,b,a)EndSub该程序的运行结果是()。

    有如下函数过程:Functionsecproc(xAsInteger,yAsInteger,zAsInteger)secproc=3*yz2*xEndFunctionPrivateSubCommand1_Click()DimaAsInteger,bAsInteger,cAsIntegera=2:b=3:c=4Printsecproc(c,b,a)EndSub该程序的运行结果是()。

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