以下代码的输出结果是(_____)。 data=[1, 0, 2, 0, 0] data.remove(0) print(data)
以下代码的输出结果是(_____)。 data=[1, 0, 2, 0, 0] data.remove(0) print(data)
对列表data=[1,4,1,2,8,1]执行data.remove(1)方法后,列表data将变为( ) A: [4,2,8] B: [1,4,1,2,8] C: [4,1,2,8,1] D: [1,1,2,8,1]
对列表data=[1,4,1,2,8,1]执行data.remove(1)方法后,列表data将变为( ) A: [4,2,8] B: [1,4,1,2,8] C: [4,1,2,8,1] D: [1,1,2,8,1]
以下代码的输出结果是(_____)。data=[1, 0, 2, 0, 0] data.remove(0) print(data) A: [1, 2, 0, 0] B: [1, 2] C: [0, 2, 0, 0] D: [1, 0, 2, 0]
以下代码的输出结果是(_____)。data=[1, 0, 2, 0, 0] data.remove(0) print(data) A: [1, 2, 0, 0] B: [1, 2] C: [0, 2, 0, 0] D: [1, 0, 2, 0]
Heat the soup for ten minutes, and then _______from the stove. A: you should remove it B: removing it C: to remove it D: remove it
Heat the soup for ten minutes, and then _______from the stove. A: you should remove it B: removing it C: to remove it D: remove it
Given that a scoped attribute cart exist only in a user’s session, which two, taken independently, ensure the scoped attribute cart no longer exists?() A: ${cart = null } B: <c:remove var=”cart” /> C: <c:remove var=”${cart}” /> D: <c:remove var=”cart” scope=”session” /> E: <c:remove scope=”session”>cart</c:remove> F: <c:remove var=”${cart}” scope=”session” /> G: <c:remove scope=”session”>${cart}</c:remove>
Given that a scoped attribute cart exist only in a user’s session, which two, taken independently, ensure the scoped attribute cart no longer exists?() A: ${cart = null } B: <c:remove var=”cart” /> C: <c:remove var=”${cart}” /> D: <c:remove var=”cart” scope=”session” /> E: <c:remove scope=”session”>cart</c:remove> F: <c:remove var=”${cart}” scope=”session” /> G: <c:remove scope=”session”>${cart}</c:remove>
以下哪个不是Android手机常见的应用程序?( ) A: \data\data\com.tencent.mm B: \data\data\com.tencent.mobileqq C: \data\data\com.eg.android.AlipayGphone D: \data\data\com.tencent.xin
以下哪个不是Android手机常见的应用程序?( ) A: \data\data\com.tencent.mm B: \data\data\com.tencent.mobileqq C: \data\data\com.eg.android.AlipayGphone D: \data\data\com.tencent.xin
remove
remove
已知有n个数据进行排序,下面能实现排序的是 A: data=[34,5,-6,12,87,29]data.sort() B: data=[34,5,-6,12,87,29]n=len(data)od=[]whileiwhilejifdata[j]>data[j+1]:t=data[j]data[j]=data[j+1]data[j+1]=tj+=1i+=1 C: data=[34,5,-6,12,87,29]n=len(data)i=0j=0whileiwhilejifdata[j]>data[j+1]:t=data[j]data[j]=data[j+1]data[j+1]=tj+=1i+=1print(data) D: data=[34,5,-6,12,87,29]n=len(data)i=0j=0whileiwhilejifdata[i]>data[j]:t=data[i]data[i]=data[j]data[j]=tj+=1i+=1
已知有n个数据进行排序,下面能实现排序的是 A: data=[34,5,-6,12,87,29]data.sort() B: data=[34,5,-6,12,87,29]n=len(data)od=[]whileiwhilejifdata[j]>data[j+1]:t=data[j]data[j]=data[j+1]data[j+1]=tj+=1i+=1 C: data=[34,5,-6,12,87,29]n=len(data)i=0j=0whileiwhilejifdata[j]>data[j+1]:t=data[j]data[j]=data[j+1]data[j+1]=tj+=1i+=1print(data) D: data=[34,5,-6,12,87,29]n=len(data)i=0j=0whileiwhilejifdata[i]>data[j]:t=data[i]data[i]=data[j]data[j]=tj+=1i+=1
有如下程序 #include intchange(int*data) { *data=*data%2; return(*data)+1; } main() { intdata=12; change(&data); printf("%d,",data); data=change(&data); printf("%d,",data); } 程序运行后的输出结果是()
有如下程序 #include intchange(int*data) { *data=*data%2; return(*data)+1; } main() { intdata=12; change(&data); printf("%d,",data); data=change(&data); printf("%d,",data); } 程序运行后的输出结果是()
The data collected by the statistical survey can be original data or secondary data. The relationship between the original data and secondary data is ( ) A: The original data comes from the grass-roots units, and the secondary data comes from the superior units B: Secondary data is processed from original data C: There is no necessary connection between the original data and the secondary data D: There is no difference between primary data and secondary data
The data collected by the statistical survey can be original data or secondary data. The relationship between the original data and secondary data is ( ) A: The original data comes from the grass-roots units, and the secondary data comes from the superior units B: Secondary data is processed from original data C: There is no necessary connection between the original data and the secondary data D: There is no difference between primary data and secondary data