• 2022-06-04 问题

    def is_odd(n):return n%2 == 1lst1 = filter(is_odd,[1,2,3,4,5,6,7,8,9,10])list(lst1)值为?

    def is_odd(n):return n%2 == 1lst1 = filter(is_odd,[1,2,3,4,5,6,7,8,9,10])list(lst1)值为?

  • 2022-06-30 问题

    Filter的[filter-mapping]元素的子元素不包括[dispatcher]元素。

    Filter的[filter-mapping]元素的子元素不包括[dispatcher]元素。

  • 2022-06-19 问题

    简述配置文件中,Filter的[filter-mapping]元素的作用。

    简述配置文件中,Filter的[filter-mapping]元素的作用。

  • 2022-06-30 问题

    如果有如下配置,当访问应用程序中的adduser.jsp时,使用的过滤器是( )。 &#91;filter-mapping&#93;[br][/br] &#91;filter-name&#93;filter1&#91;/-name&#93; &#91;url-pattern&#93;/*&#91;/-pattern&#93; &#91;/-mapping&#93; &#91;filter-mapping&#93; &#91;filter-name&#93;filter2&#91;/-name&#93; &#91;url-pattern&#93;*.html&#91;/-pattern&#93; &#91;/-mapping&#93; &#91;filter-mapping&#93; &#91;filter-name&#93;filter3&#91;/-name&#93; &#91;url-pattern&#93;*.jsp&#91;/-pattern&#93; </filter-mapping A: filter1 B: filter2 C: filter3 D: 无

    如果有如下配置,当访问应用程序中的adduser.jsp时,使用的过滤器是( )。 &#91;filter-mapping&#93;[br][/br] &#91;filter-name&#93;filter1&#91;/-name&#93; &#91;url-pattern&#93;/*&#91;/-pattern&#93; &#91;/-mapping&#93; &#91;filter-mapping&#93; &#91;filter-name&#93;filter2&#91;/-name&#93; &#91;url-pattern&#93;*.html&#91;/-pattern&#93; &#91;/-mapping&#93; &#91;filter-mapping&#93; &#91;filter-name&#93;filter3&#91;/-name&#93; &#91;url-pattern&#93;*.jsp&#91;/-pattern&#93; </filter-mapping A: filter1 B: filter2 C: filter3 D: 无

  • 2022-05-26 问题

    表达式list(filter(lambda x:x.isupper(),&#91;‘a’,’B’,’aB’&#93;))的值为(______ )。

    表达式list(filter(lambda x:x.isupper(),&#91;‘a’,’B’,’aB’&#93;))的值为(______ )。

  • 2022-06-04 问题

    给一段代码defis_odd(n):returnn%2==0newlist=filter(is_odd,&#91;1,2,3,4,5,6,7,8,9,10&#93;)foriteminnewlist:print(item)其输出结果是? A: [2,4,6,8,10] B: [1,3,5,7,10] C: [1,3,5,7,9] D: [1,3,5,6,9]

    给一段代码defis_odd(n):returnn%2==0newlist=filter(is_odd,&#91;1,2,3,4,5,6,7,8,9,10&#93;)foriteminnewlist:print(item)其输出结果是? A: [2,4,6,8,10] B: [1,3,5,7,10] C: [1,3,5,7,9] D: [1,3,5,6,9]

  • 2022-06-30 问题

    如果有如下配置,当访问应用程序中的adduser.jsp时,使用的过滤器顺序为( )。 &#91;filter-mapping&#93;[br][/br] &#91;filter-name&#93;filter1&#91;/-name&#93; &#91;url-pattern&#93;/*&#91;/-pattern&#93; &#91;/-mapping&#93; &#91;filter-mapping&#93; &#91;filter-name&#93;filter2&#91;/-name&#93; &#91;url-pattern&#93;*.html&#91;/-pattern&#93; &#91;/-mapping&#93; &#91;filter-mapping&#93; &#91;filter-name&#93;filter3&#91;/-name&#93; &#91;url-pattern&#93;*.jsp&#91;/-pattern&#93; </filter-mapping A: filter1、filter2、filter3 B: filter1、filter2 C: filter1、filter3 D: filter2、filter3

    如果有如下配置,当访问应用程序中的adduser.jsp时,使用的过滤器顺序为( )。 &#91;filter-mapping&#93;[br][/br] &#91;filter-name&#93;filter1&#91;/-name&#93; &#91;url-pattern&#93;/*&#91;/-pattern&#93; &#91;/-mapping&#93; &#91;filter-mapping&#93; &#91;filter-name&#93;filter2&#91;/-name&#93; &#91;url-pattern&#93;*.html&#91;/-pattern&#93; &#91;/-mapping&#93; &#91;filter-mapping&#93; &#91;filter-name&#93;filter3&#91;/-name&#93; &#91;url-pattern&#93;*.jsp&#91;/-pattern&#93; </filter-mapping A: filter1、filter2、filter3 B: filter1、filter2 C: filter1、filter3 D: filter2、filter3

  • 2022-06-04 问题

    What kind of filter is used to extract a single-freq. harmonic from the harmonic components contained in square wave? A: Low-pass Filter B: High-pass Filter C: Band-pass Filter D: Band-elimination Filter

    What kind of filter is used to extract a single-freq. harmonic from the harmonic components contained in square wave? A: Low-pass Filter B: High-pass Filter C: Band-pass Filter D: Band-elimination Filter

  • 2022-07-28 问题

    已知 f=lambda a:a>0, lst=&#91;-1,0,1&#93;,则表达式 list( filter(f,lst) ) 的结果为

    已知 f=lambda a:a>0, lst=&#91;-1,0,1&#93;,则表达式 list( filter(f,lst) ) 的结果为

  • 2022-06-14 问题

    Map对于map和filter方法使用正确的是() A: Map本身没有map和filter方法 B: constmap0=newMap().set(1,’a’).set(2,’b’).set(3,’c’);constmap1=newMap([...map0].filter(([k,v])=>k<3));//产生Map结构{1=>’a’,2=>’b’} C: newMap().set(1,’a’).set(2,’b’).set(3,’c’)..filter(([k,v])=>k<3)//产生Map结构{1=>’a’,2=>’b’} D: constmap2=newMap([...map0].map(([k,v])=>[k*2,’_’+v]));//产生Map结构{2=>’_a’,4=>’_b’,6=>’_c’}

    Map对于map和filter方法使用正确的是() A: Map本身没有map和filter方法 B: constmap0=newMap().set(1,’a’).set(2,’b’).set(3,’c’);constmap1=newMap([...map0].filter(([k,v])=>k<3));//产生Map结构{1=>’a’,2=>’b’} C: newMap().set(1,’a’).set(2,’b’).set(3,’c’)..filter(([k,v])=>k<3)//产生Map结构{1=>’a’,2=>’b’} D: constmap2=newMap([...map0].map(([k,v])=>[k*2,’_’+v]));//产生Map结构{2=>’_a’,4=>’_b’,6=>’_c’}

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