3 、 反应 X + 2Y → Z 是一个 2.5 级反应,下面的速率方程式中,可能正确的是 . . (A) v = k c (X)[ c (Y)] 2 ; (B) v = k c (X)[ c (Y)] 3/2 ; (C) v = k [ c (X)] 2 c (Y) ; (D) v = k [ c (X)] 0 [ c (Y)] 2
3 、 反应 X + 2Y → Z 是一个 2.5 级反应,下面的速率方程式中,可能正确的是 . . (A) v = k c (X)[ c (Y)] 2 ; (B) v = k c (X)[ c (Y)] 3/2 ; (C) v = k [ c (X)] 2 c (Y) ; (D) v = k [ c (X)] 0 [ c (Y)] 2
下面程序的执行结果是 ______。 int k; for (k=10 ; k<3 ; k--) { if (k%3) k--; -k; k; cout<<k<< ", "; } A: 6, 3 B: 7, 4 C: 6, 2 D: 7, 4, 1
下面程序的执行结果是 ______。 int k; for (k=10 ; k<3 ; k--) { if (k%3) k--; -k; k; cout<<k<< ", "; } A: 6, 3 B: 7, 4 C: 6, 2 D: 7, 4, 1
【单选题】下面程序段的输出结果是 () 。 int k,a[3][3]={1,2,3,4,5,6,7,8,9}; for (k=0;k<3;k++) printf(“%d”,a[k][2-k]); ( A ) 3 5 7 ( B ) 3 6 9 ( C ) 1 5 9 ( D ) 1 4 7 A. 3 5 7 B. 3 6 9 C. 1 5 9 D. ( A ) 1 4 7
【单选题】下面程序段的输出结果是 () 。 int k,a[3][3]={1,2,3,4,5,6,7,8,9}; for (k=0;k<3;k++) printf(“%d”,a[k][2-k]); ( A ) 3 5 7 ( B ) 3 6 9 ( C ) 1 5 9 ( D ) 1 4 7 A. 3 5 7 B. 3 6 9 C. 1 5 9 D. ( A ) 1 4 7
3、反应X+2Y→Z是一个2.5级反应,下面的速率方程式中,可能正确的是..(A)v=kc(X)[c(Y)]2;(B)v=kc(X)[c(Y)]3/2;(C)v=k[c(X)]2c(Y);(D)v=k[c(X)]0[c(Y)]2 A: (A) v = k c (X)[c (Y)]2; B: (B) v = k c (X)[ c (Y)]3/2; C: (C) v = k[c (X)]2 c (Y); D: (D) v = k [c (X)]0[ c (Y)]2
3、反应X+2Y→Z是一个2.5级反应,下面的速率方程式中,可能正确的是..(A)v=kc(X)[c(Y)]2;(B)v=kc(X)[c(Y)]3/2;(C)v=k[c(X)]2c(Y);(D)v=k[c(X)]0[c(Y)]2 A: (A) v = k c (X)[c (Y)]2; B: (B) v = k c (X)[ c (Y)]3/2; C: (C) v = k[c (X)]2 c (Y); D: (D) v = k [c (X)]0[ c (Y)]2
如下电路图,UBEQ = 0.7 V,RB1= 51 kΩ,RB2= 10 kΩ, RC = 3 kΩ, RE = 500Ω, RL = 3 kΩ,VCC = 12V, 则UB的值近似是( )V。1e118854ee73e17044a453474475b688.png
如下电路图,UBEQ = 0.7 V,RB1= 51 kΩ,RB2= 10 kΩ, RC = 3 kΩ, RE = 500Ω, RL = 3 kΩ,VCC = 12V, 则UB的值近似是( )V。1e118854ee73e17044a453474475b688.png
After exiting the loop, the value of k is ( ).for k=1:3:11 end k A: 3 B: 11 C: 10 D: 7
After exiting the loop, the value of k is ( ).for k=1:3:11 end k A: 3 B: 11 C: 10 D: 7
牛顿基本插值公式,填空使程序完整。 x=1:7; y=[5 3 2 1 2 4 7]; syms p; plot(x,y,'o','linewidth',3); n=length(x); for k=1:n for j=【1】 y(j) = (y(j)-y(j-1))/【2】; end end v=0; w=1; for k=1:n v=v+【3】; w=w*(p-x(k)); end s=subs(v,'p','x') s=collect(s) ezplot(s,1,7)
牛顿基本插值公式,填空使程序完整。 x=1:7; y=[5 3 2 1 2 4 7]; syms p; plot(x,y,'o','linewidth',3); n=length(x); for k=1:n for j=【1】 y(j) = (y(j)-y(j-1))/【2】; end end v=0; w=1; for k=1:n v=v+【3】; w=w*(p-x(k)); end s=subs(v,'p','x') s=collect(s) ezplot(s,1,7)
V={7, 2, 3, 11, 17, 5, 19, 13} After two scan exchange of V, V[6] = V={7, 2, 3, 11, 17, 5, 19, 13},对V进行两次扫描交换后V[6] =
V={7, 2, 3, 11, 17, 5, 19, 13} After two scan exchange of V, V[6] = V={7, 2, 3, 11, 17, 5, 19, 13},对V进行两次扫描交换后V[6] =
已知列表x=[3, 5, 6, 7, 9],那么x[::-1]的结果是 A: [3, 9] B: [3, 5, 6, 7, 9] C: [3, 5, 6, 7] D: [9, 7, 6, 5, 3]
已知列表x=[3, 5, 6, 7, 9],那么x[::-1]的结果是 A: [3, 9] B: [3, 5, 6, 7, 9] C: [3, 5, 6, 7] D: [9, 7, 6, 5, 3]
反应X+2Y→Z是一个2.5级反应,下面的速率方程式中,可能正确的是()(A)v=kc(X)[c(Y)]2;(B)v=kc(X)[c(Y)]3/2;(C)v=k[c(X)]2c(Y);(D)v=k[c(X)]0[c(Y)]2 A: v = k c (X)[c (Y)]2; B: v = k c (X)[ c (Y)]3/2; C: v = k[c (X)]2 c (Y); D: v = k [c (X)]0[ c (Y)]2
反应X+2Y→Z是一个2.5级反应,下面的速率方程式中,可能正确的是()(A)v=kc(X)[c(Y)]2;(B)v=kc(X)[c(Y)]3/2;(C)v=k[c(X)]2c(Y);(D)v=k[c(X)]0[c(Y)]2 A: v = k c (X)[c (Y)]2; B: v = k c (X)[ c (Y)]3/2; C: v = k[c (X)]2 c (Y); D: v = k [c (X)]0[ c (Y)]2